Question
Asked Oct 13, 2019

Three-point charges are located on the x-axis. The first charge, q1 = 10.0 uC (micro C), is at x = -1.00 m the second charge, q2 = 60.0 uC (micro C), is at the origin, and the third charge, q3 = -30.0 uC (micro C), is located at x = 2.00 m. What is the force on q2

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Expert Answer

Step 1

Given information:

Charge of the first charge (q1) = 10 µC

Location of the charge on x-axis (x1) = -1.00 m

Charge of the 2nd charge (q2) = 60 µC

Location of charge on x-axis (x2) = 0.00

Charge on the 3rd charge (q3) = -30 µC

Location of charge on x-axis (x3) = 2.00 m

Step 2

From coulomb’s law the force acting between two-point charges is given as:

F =
r2
Where "k" is the proportionality constant = 9 x 10° N.m2/C2
"q1" and "2" are the magnitude of charge's
"r" is the distance between them
In the given problem the given situation is represented as follows:
ο-30 μC
α- 10 μC
α-60 μC
F23
F21
1 m
2 m
Where "F21 is the force caused by the Q1 on Q2, since both are +ve charges the force
between them is repulsive.
"F23" is the Force caused by the charge Q3 on Q2, since both are of opposite charges the force
between them is attractive
The direction of the forces is shown in the figure
help_outline

Image Transcriptionclose

F = r2 Where "k" is the proportionality constant = 9 x 10° N.m2/C2 "q1" and "2" are the magnitude of charge's "r" is the distance between them In the given problem the given situation is represented as follows: ο-30 μC α- 10 μC α-60 μC F23 F21 1 m 2 m Where "F21 is the force caused by the Q1 on Q2, since both are +ve charges the force between them is repulsive. "F23" is the Force caused by the charge Q3 on Q2, since both are of opposite charges the force between them is attractive The direction of the forces is shown in the figure

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Step 3

From the figure we can write the force act...

F F21F23
We can get F21 as:
(9x 10)x10μCx60μC
- 5.4 Ν
F21
(1 m)2
r2
help_outline

Image Transcriptionclose

F F21F23 We can get F21 as: (9x 10)x10μCx60μC - 5.4 Ν F21 (1 m)2 r2

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