TIS G uestion P lesterol um 160mg Carbohydrate ary Fiber< Sugars <9 Aser Question Help If we sample from a small finite population without replacement, the binomial distribution should not be used because the events are not independent. If sampling is done without replacement and the outcomes belong to one of two types, we can use the hypergeometric distribution. If a population has A objects of one type, while the remaining B objects are of the other type, and if n objects are sampled without replacement, then the probability of getting x objects of type A and n- x objects of type B under the hypergeometric distribution is given by the following formula. In a lottery game, a bettor selects six numbers from 1 to 58 (without repetition), and a winning six-number combination is later randomly selected. Find the probabilities of getting exactly two winning numbers with one ticket. (Hint: Use A = 6, B = 52, n = 6, and x= 2.) udes in 1g A! B! (A + B)! (A + B- n)!n! P(x) = (A – x)!x! (B - n +x)!(n – x)! P(2) = (Round to four decimal places as needed.) CUTNAR Car

Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter70: Complex Practical Machine Applications
Section: Chapter Questions
Problem 2A: Determine the length of side b. Round the answer to 3 decimal places.
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TIS G uestion P
lesterol
um 160mg
Carbohydrate
ary Fiber<
Sugars <9
Aser
Question Help
If we sample from a small finite population without replacement, the binomial distribution should not be used because the events are not independent. If sampling is done without replacement and the outcomes belong
to one of two types, we can use the hypergeometric distribution. If a population has A objects of one type, while the remaining B objects are of the other type, and if n objects are sampled without replacement, then the
probability of getting x objects of type A and n- x objects of type B under the hypergeometric distribution is given by the following formula. In a lottery game, a bettor selects six numbers from 1 to 58 (without repetition),
and a winning six-number combination is later randomly selected. Find the probabilities of getting exactly two winning numbers with one ticket. (Hint: Use A = 6, B = 52, n = 6, and x= 2.)
udes
in 1g
A!
B!
(A + B)!
(A + B- n)!n!
P(x) =
(A – x)!x! (B - n +x)!(n – x)!
P(2) =
(Round to four decimal places as needed.)
CUTNAR
Car
Transcribed Image Text:TIS G uestion P lesterol um 160mg Carbohydrate ary Fiber< Sugars <9 Aser Question Help If we sample from a small finite population without replacement, the binomial distribution should not be used because the events are not independent. If sampling is done without replacement and the outcomes belong to one of two types, we can use the hypergeometric distribution. If a population has A objects of one type, while the remaining B objects are of the other type, and if n objects are sampled without replacement, then the probability of getting x objects of type A and n- x objects of type B under the hypergeometric distribution is given by the following formula. In a lottery game, a bettor selects six numbers from 1 to 58 (without repetition), and a winning six-number combination is later randomly selected. Find the probabilities of getting exactly two winning numbers with one ticket. (Hint: Use A = 6, B = 52, n = 6, and x= 2.) udes in 1g A! B! (A + B)! (A + B- n)!n! P(x) = (A – x)!x! (B - n +x)!(n – x)! P(2) = (Round to four decimal places as needed.) CUTNAR Car
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