Titration of 0.2121 g of primary standard Na,C,0, (133.999 g/mol) required 21.66 mL of KMnO, (158.034 g/mol) to reach the end point.Calculate the molar concentration of KMNO,? 2 MnO, + 5 C,0,2+ 16 H+ -2 Mn² 10 CO, +8 H201. 00.01462. 00.02923. 00.007314. 00.1462

Answered: Image /qna-images/answer/73d0be78-d6cd-4477-b5a8-a262c1950128.jpg

Answered: Titration of 0.2121 g of primary…

Titration of 0.2121 g of primary standard NagC;0, Calculate the molar concentration of KMnO,? 2 Mno,+ 5 C,0, + 16 H+ 2 Mn 10 CO, +8 H;0 1. 00.0146 2. 00.0292 3. 00.00731 4. 00.1462

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter17: Principles Of Chemical Reactivity: Other Aspects Of Aqueous Equilibria

Section17.6: Equilibria Involving Complex Ions

Problem 1.2ACP: What is the minimum volume of 0.0071 M NaCN(aq) necessary to dissolve the gold from 1.0 metric ton...

See similar textbooks

Related questions

Q: aria wants to determine the concentration of Calcium ions in water from their well. She used a 100.0…

A: Maria wants to determine the concentration of Calcium ions in water from their well. She used a…

Q: On titrating 20 ml of 0.1 M KCI with O.1 M AGNO3. (For AgCI, Ksp = 1.82 X 1o: 10). 1. The volume of…

Q: Find the concentration of 50.0 ml of an acidified Fe2+ solution if 18.72ml of 0.01500M solution of…

A: According to the mole concept, in terms of mass, the amount of substance in moles is equal to the…

Q: Determine the molarity of the 10.00 mL standard EDTA solution titrated using 1.000 g zinc sulfate in…

Q: 1. Calculate the potential as a function of titrant volume when 50 mL of 0.100 M Fe* is titrated…

A: Given, Titration of 50mL 0.100M Fe2+ solution is done with 0.100M Ce4+ solution. Before the…

Q: titration of 50.00 mL of 0.1100 M Fe3+ with 0.07750 M Sn2+ is carried out. The analytical reaction…

Q: Calculate the % KHP of 1.294 g sample which requires 48.25 mL of NaOH solution during the titration.…

A: Molarity of NaOH is not provided in the question. So I aassumed it to be X molar. Just put the value…

Q: A 0.1510 g KHP (MW = 204.22 g/mol) sample required a volume of 57.04 mL of NaOH solution to reach a…

Q: Determine the molar concentration of an EDTA solution of which 26.44 mL were required to titrate a…

Q: A 0.1510 g KHP (Mw = 204.22 g/mol) sample required a volume of 57.04 mL of NaOH solution to reach a…

A: KHP reacts with sodium hydroxide to form NaKPH and water. One mole of KHP reacts with one mole of…

Q: Determine the % w/w chloride in the sample. A 0.3285 g sample containing chloride and inert…

A: The % w/w chloride in the sample has to be given, Given : The mass of the solute is 0.3285 g. The…

Q: A 0.3285 g sample containing chloride and inert material is titrated with 0.1012 M AgNO3, requiring…

Q: How is coulometric titration done? Explain step by step.

A: coulometric titration - Coulometric titration is an absolute determination technique in which the…

Q: Titration of 0.2121 g of primary standard Na C,0, (133.999 g/mol) required 21.66 mL of KMnO,…

A: Given that: Mass of Na2C2O4 = 0.2121g Molar mass of Na2C2O4 = 133.999g/mol Moles of Na2C2O4 =…

Q: Calculate the volume of 0.0500 M EDTA need to titrate 25.6 mL of 0.0600 M Mg(NO3)2.

A: EDTA is ethylenediaminetetraacetic acid which is an indicator. It has 2 amino and 4 carboxyl groups.…

Q: For complexometric titration of Ca (II) ions in the shell of an egg sample weighing 59,427 g, the…

A: From the result of complexometric titration, concentration of Ca2+ in the egg shell has to be…

Q: Calculate the concentration of the Na2S2O3.

A: Given, Mass of primary standard KIO3 0.1238 g Volume of sodium thiosulfate (Na2S2O3) = 41.27 mL =…

Q: A 0.72g sample of foot powder containing Zinc was titrated with 21.3mL of 0.02M EDTA. Calculate the…

Q: A sample of water (200 mi.) was titrated by 0.05 M HZS04, The bitration completed when the color…

Q: For the titration of 50.00 mL of 0.300 M RbC7H5O2 (WB) with 0.200 M HNO3 (SA). Ka (HC7H5O2) = 6.3 x…

Q: Exp: 5: A 0.8040 g an iron one is dissolved in acid. The iron is then reduced Fe2* and titrated with…

A: The titration involves the conversion of ferrous into ferric,

Q: Q2// (A) Calculate the number of meq. involved in a titration that required 15.4 ml of 0.3N KMNO4…

A: Given data; a) Normality of KMnO4 = 0.3 N ; Volume of KMnO4 = 15.4 mL b) Total Volume of EDTA added…

Q: For the titration of 50.00 mL of 0.300 M RbC7H5O2 (WB) with 0.200 M HNO3 (SA). Ka (HC7H5O2) = 6.3 x…

Q: Calculate the equivalence point potential for the titration of 50.0 mL of 0.02 M Ce+4 with 33.33 mL…

A: 50.0 mL of 0.02 M of Ce+4 is titrated with 33.33 mL of 0.03 M Cu+2 .We have to calculate the…

Q: The DO of a water sample used in a steel industry was tested by Winkler’s method. The following…

A: A question based on introduction to chemistry that is to be accomplished.

Q: The Zn in a 260-g sample of foot powder was titrated with 2 L of 0.5 M EDTA. Calculate the percent…

A: Given that - Mass of Sample of Zn = 260 g Volume of EDTA Solution = 2 L Molarity of EDTA Solution…

Q: Calculate the volume of 0.0602 M EDTA needed to titrate 11.63 mL of 0.0725 M Mg(NO3)2.

Q: The potential at equivalence point of the following titrations will be dependent of the pH of the…

A: Potentiometric titration is another titration method where potential difference of analyte is…

Q: A 10 mL sample of sulfuric acid solution required 16.85 mL of NaOH solution in a titration. Each mL…

A: TITRATION Titration is a method of quantitative analysis for the determination of the concentration…

Q: A titration of 50.00 mL of 0.1100 M Fe3+ with 0.07750 M Sn2+ is carried out. The analytical reaction…

A: Redox process is combination oxidation and reduction process

Q: You want to measure the concentration of carbonate (CO32-) in a mildly basic solution by using an…

A: The concentration and the number of moles of Ca2+ ion in the filtered solution is;…

Q: In the titration of 25.00 ml of 0.1000 M AgNO, with 0.2000 M KSCN, Pafter the addition of 12.5 ml…

Q: e the Esystem values after the addition of 30.00 mL of 0,0500 M HCIO3 to 25,00 mL 0 M NaAuCl4: 3(aq)…

Q: Titration of I 2 produced from 0.1500 g of primary-standard-grade KIO 3 required 42.30 mL of sodium…

A: Answer is explained below. Ans: The concentration of the Na2S2O3 is 0.099 M.

Q: what is the value of magnesium in ppm in the sample?(Mg:24 g/mol)

A: The titration reaction is: Mg2+ + EDTA-4 ====> Mg(EDTA)-2 Let us first calculate moles of EDTA…

Q: For the titration of 50.00 mL of 0.300 M RbC7H5O2 (WB) with 0.200 M HNO3 (SA). Ka (HC7H5O2) = 6.3 x…

A: The question is based on the concept of titrations. it involves titration of a weak base with a…

Q: Determine the molarity of the 10.00 mL standard EDTA solution titrated using 1.000 g zinc sulfate in…

A: 1- First determine the moles of ZnSO4 : Moles = [ mass / molar mass ] Moles = [ 1.000g /…

Q: In titration of 50 ml 0.1 M Mn2+ with 0.01 M EDTA (pH = 7), what is pMn2+ when 100 ml EDTA is added?

Q: In titration of 100 ml 0.3 Mn2+ with 0.7 M EDTA (pH = 7), when 50 ml EDTA is added what is pMn²+?…

A: Given, In titration of 100 ml 0.3 Mn2+ with 0.7 M EDTA (pH = 7), when 50 ml EDTA is added. We have…

Q: CALCULATE THE THEORETICAL VOLUME (V theoretical) 0.1 M OF SODIUM NITRITE SOLUTION NANO2, WHICH IS…

Q: which of the following is the concentration of the EDTA solution in terms of molarity

A: Solution: Here given experimente is carried out to know concentration of EDTA solution. Where,…

Q: 63.0 mL of Ca(OH)2 solution was titrated with 21.5 mL of 0.467 MHNO3. Determine the molarity of the…

A: Balanced reaction is - CaOH2 + 2HNO3 → CaNO32 + 2H2O Here given--- Volume…

Q: DETERMINE THE THEORETICAL VOLUME OF TITRANT (V theoretical) WITH THE QUANTITATIVE DETERMINATION OF…

A: Solutions- Given data- About 0.25 g (precise charge) of the substance is dissolved in a mixture of…

Q: A 100.0 mL sample of 0.18 M HCIO, (Strong acid) is titrated with 0.27 M LIOH. Determine the pft of…

A: The pH is to be calculated

Q: Calculate the potential at the equivalence point in the titration of 100 mL 0.100 M Fe2+ in 0.500 M…

A: The electrode potential of the cell is defined as the potential difference across the electrodes of…

Q: 150.0 mL of 0.2105 M nitric acid was added to 1.3415 g calcium carbonate. The excess acid was back…

A: Given : Volume of Nitric acid=150.0 ml Molarity of nitric acid=0.2105 M Mass of calcium…

Q: . The brine solution has a significant amount of chloride, and it is determined by the Volhard…

A: Volume of AgNO3 = 15.25 ml Concentration of AgNO3 = 0.1163 M Volume of KSCN = 3.28ml Concentration…

Q: For the titration of 50.00 mL of 0.300 M RbC7H5O2 (WB) with 0.200 M HNO3 (SA). Ka (HC7H5O2) = 6.3 x…

A: After addition of strong acid we can observe only strong acid HNO3 remains in the solution.

Q: 0.316 grams of a sample containing chloride is taken and treated with an excess of 48.5 mL of 0.11 M…

A: Here we are required to find the percentage of chloride present in the sample

Q: 50 mL of a sample known to contain Mg+2 was taken and titrated with 0.075 M EDTA standard solution…

Question

Titration of 0.2121 g of primary standard Na,C,0, (133.999 g/mol) required 21.66 mL of KMnO, (158.034 g/mol) to reach the end point.
Calculate the molar concentration of KMNO,? 2 MnO, + 5 C,0,2+ 16 H+ -
2 Mn² 10 CO, +8 H20
1. 00.0146
2. 00.0292
3. 00.00731
4. 00.1462

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

You have performed an iodimetric titration using a commercial vitamin C tablet. Based on the following information below, calculate the %(w/w) of vitamin C(MM=176.16 g/mol) in the tablet: Mass of tablet dissolved in 250.0 mL: 5.422 g Aliquot volume of sample titrated: 25.00 mL Concentration of KIO3: 0.023 M Final burrette volume: 41.31 mL Initial burrette volume: 8.89 mL Blank volume: 0.14 mL
0.0585g of Na2C2O4, 10 mL of distilled water and 2 M H2SO4 were added to adjust the KMnO4 solution prepared as 0.1M. Heating process was carried out and 8.4mL of titrant was consumed as a result of titration. Calculate the true concentration of potassium permanganate accordingly.
A sample of 0.10 M CH3COOH(aq) of volume 25.0 cm3 is titrated with 0.10 M NaOH(aq). The Ka for CH3COOH is 1.8 x 10-5. (a) What is the pH of 0.10 M CH3COOH(aq)? (b) What is the pH after the addition of 10.0 cm3 of 0.10 MNaOH(aq)? (c) What volume of 0.10 M NaOH(aq) is required to reach halfway to the stoichiometric point? (d) Calculate the pH at that halfway point. (e) What volume of 0.10 M NaOH(aq) is required to reach the stoichiometric point? (f) Calculate the pH at the stoichiometric point.
Maria wants to determine the concentration of Calcium ions in water from their well. She used a 100.0 mL water sample, and its pH was adjusted to 10 and 3 drops of the indicator were added. She used 2.500 mL of 0.09945 M EDTA to reach the endpoint. What is the concentration (mg/L) of calcium ion in the sample? Identify the classification of water given the reference. Reference: 0 to 60 mg/L Ca is classified as soft, 61 to 120 mg/L as moderately hard; 121 to 180 mg/L as hard; and more than 180 mg/L as very hard
25.00 mL of a solution containing KIO4 is treated with excess potassium iodide. IO4- + 8H+ + 7I- → 4I2 + 4H2O The resulting solution is titrated with 0.15 M sodium thiosulfate pentahydrate. The average titre was 21.76 mL. I2 + 2S2O32- → 2I- + S4O62- What is the concentration of the sodium thiosulfate solution as a percentage (w/v)
Titration of 25.0 mL of a 0.0500 M Zn2+ solution with 0.0550 M EDTA in a solution buffered at pH 8. Assume that the temperature is 25 oC and that the formation constant for Zn2+ is 3.13 x 1016 at this temperature. What is the conditional formation constant for Zn at this pH?
Titration of 50.00 mL of 0.04715 M Na2C2O4 required 39.25 mL of a potassium permanganate solution. 2MnO4- + 5C2O4-2 +16H+ -> 2Mn2+ + 10CO2(g) + 8H2O Calculate the molar concentration of the KMnO4 solution What molecules would interfere with the titrimetric analysis?
The SO2 present in air is mainly responsible for the phenomenon of acid rain. The concentration of SO2 can be determined by titrating against a standard permanganate solution as follows: 5SO2 + 2MnO4- + 2H2O ---> 5SO42- + 2Ms2 + 4H+ Calculate the number of grams of SO2 in a sample of air if 4.90mL of 0.00700M KMnO4 solution are required for the titration. Be sure your answer has the correct number of significant digits.
Titration of 25.0 mL of a 0.0500 M Zn2+ solution with 0.0550 M EDTA in a solution buffered at pH 8. Assume that the temperature is 25 oC and that the formation constant for Zn2+ is 3.13 x 1016 at this temperature. What is the pZn of the solution after 30 mL of titrant have been added?
Q: The solubility product of Zn(OH)2 at 25oC is 3.0 x 10-6 M3. Calculate the solubility of Zn(OH)2 in water in gdm-3. [Ar: Zn = 65.5; O = 16; H = 1] The Mr for Zn(OH)2 is 99.5. When I multiply it with Ksp, I didn't get the same answer as the given answer which is 0.904 gdm-3.
Suppose you are given 0.0856ppm to be the concentration of dissolved lead found in pond water after dilution factor of 1:100 in 100ml volumetric flask and the other sample is diluted at the dilution factor of 1:2 and the concentration is 2.14ppm. How would you comment on the amount of lead in pond water
A 25.0025.00 mL solution of 0.088300.08830 M NaINaI is titrated with 0.051500.05150 M AgNO3AgNO3. Calculate pAg+pAg+ following the addition of the given volumes of AgNO3AgNO3. The KspKsp of AgIAgI is 8.3×10−178.3×10−17. 37.40 mLpAg+=37.40 mLpAg+= VepAg+=VepAg+= 47.30 mLpAg+=47.30 mLpAg+=