QUESTION 2 Titration of a 100.0 mL aliquot of deep well water sample for total hardness requires 28.90 mL of 0.01150 M EDTA. The total hardness of the sample in ppm CaCO3 (MM=100.0875): O 332.6 170.0 166.3 330.0
Q: Calculate the pCa for the titration of 50 ml of 0.02 M Ca2+ at pH = 8 with 0.4 M EDTA at the…
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Q: Question 5: A 200.00-mL sample containing possible mixture of NaOH, Na2CO3, and/or NaHCO3 is diluted…
A: The reaction for phenolphthalein indicator is If ‘a’ is the number of moles of NaOH and ‘b’ is the…
Q: An EDTA solution was prepared by dissolving the disodium salt in 1 L of water. It was standardized…
A: Mass of CaCO3 = 0.5063 gMolecular mass of CaCO3 = 100.08 gmol
Q: 11. A 3.00-L sample of urban air was bubbled through a solution containing 50.00 mL of 0.0116 M…
A: Given that Volume of sample of urban air=3L Molarity of Ba(OH)2 solution=0.0116M Volume of Ba(OH)2…
Q: Find the concentration of 50.0 ml of an acidified Fe2+ solution if 18.72ml of 0.01500M solution of…
A: According to the mole concept, in terms of mass, the amount of substance in moles is equal to the…
Q: 25 ml of 0.05M Hg2(NO3)2 was titrated with 0.06M KIO3 Hg2*2 + 2103 == Hg(I03)2 Ksp= 1.3x10-18…
A: Given data, Molarity of Hg2(NO3)2 = 0.05M Volume of Hg2(NO3)2 = 25.0mL = 0.025L Molarity of KIO3 =…
Q: Volhard method. A total of 50.00 ml of 0.1048M AgNO3 is added to the sample and 15.38 ml of 0.3116 M…
A: Given that - Mass of Chloride containing sample = 10.6 gram Volume of AgNO3 = 50.00 mL…
Q: Suppose Missy bon bon have 20.3 L sample of gas that contains an impurity, CO. The sample was then…
A:
Q: halogens in organic compounds uses an argentometric titration. To 50 mL50 mL of anhydrous ether is…
A: Given that Mass of AgNO3 = 0.02916 Molar mass of AgNO3 = 171
Q: find the total hardness for water of lake contains (9.83 x10* ( m) of hco3, (1.25x 10 m) of…
A: Solution - According to the question - Given - The hardness of water is the sum of the…
Q: Question 11 A mixture containing KCI (74.5513 g/mol) is analyzed by the Mohr method. A 0.500-g of…
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Q: Procedure: 0.0402 g of water was titrated with Fisher's reagent according to the pharmacopoeial…
A: The T-factor for the mentioned titration can be calculated using the expression: =0.1566×weight of…
Q: 5. A 300.0 mg sample containing Na¿CO3, NaHCO, and NaOH and inert material either alone or in some…
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Q: 6. Water sample was titrated with EDTA after pH adjustment using Eriochrome black T indicator.…
A: We are given with the volume of our water sample in mL and the volume of EDTA consumed in mL and we…
Q: Table of Results Solution 1 Saturated Borax Solution #1 Saturated Borax Solution #2 Temperature (K)…
A: Given data: Temperature T1=200C Temperature T2=40C Ksp1=8.25×10-5 Ksp2=1.85×10-5
Q: QUESTION 1 A 15-ml sample of borax solution was titrated with 0.482-M HCI. The endpoint was reached…
A: Given data: 15-mL sample of borax solution 15.28 mL of 0.482-M HCl The unbalanced equation is…
Q: What is the MW of calcium carbonate?
A: Since you have asked multiple questions, we will solve the first question for you. If you want any…
Q: Question 5/ 10 If 10.0 ml of an unknown sample of phosphorie acid was titrated against 0.12 M…
A: Volume of phosphoric acid=10.0mL Concentration of NaOH=0.12M Volume of NaOH=10.30mL Concentration of…
Q: 10 8 - 6. 4 - 2- 5 10 15 20 25 30 35 40 45 50 Volume of titrant (mL) is Hd
A: A question based on acid base titration that is to be accomplished.
Q: B KUAC in 100 ml. Ans. 4.53. 850 ml 0.1 M NH, is mixed with 100 ml 0.1 M HCI. What is the pi df (the…
A: Formula used :- Concentration of H+ = number of moles of acid - number of moles of base / total…
Q: A 50.00-mL aliquot of solution containing 0.310 of MgSO4 (FM 120.37) in 0.500 L required 37.77 mL of…
A: Given, 50.00-mL aliquot of solution containing 0.310 g of MgSO4 (FM 120.37) in 0.500 L required…
Q: 1093-g sample of impure Na2CO3 was analyzed by residual precipitimetry. After adding 50.00 mL of…
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Q: 1. Solution A has 10mL containing 0.10 M NaCl and 10 M KNO3 while Solution B has 10 mL of 0.10 M…
A: Ionic strength is the measure of the total ionic species present in the solution.
Q: Rp. 4 Voina method n experiment of determination of KBr (g%) by volhard met flask; - 15ml KBr was…
A: The question is based on quantitative estimation of potassium bromide present in the given sample.…
Q: On titrating 100 ml of 0.02 M KCI with 0.2 M AgNO3 Calculate the pAg after addition of 15 ml AgN03.…
A: Given: Concentration of AgNO3 = 0.2 M Concentration of KCl = 0.02 M Volume of KCl = 100 mL = 0.100 L…
Q: 1. Sodium oxalate crystals (0.1234 g, MM=134) required 15.67 ml of KMNO, solution to titrate. Find…
A: the solution is as follows:
Q: Standardization of EDTA was done using MgSO4 standard wherein a 50-mL aliquot of solution obtained…
A: Mass of MgSO4 = 0.480 g in 500 mL (0.500 L) Volume of MgSO4 = 50 mL Volume of EDTA = 39.4 mL Mass…
Q: recipitation titration curves of 20 mL of 0.15 M KBr and KI solutions with 0.10 M AGNO3 and that the…
A: More stteper is the titration curve more faster precipitation will occur. Lower the Ksp value ,…
Q: A 10.00mL sample of alcoholic ethyl acetate was diluted to 100.00 mL. 20.00 mL was aliquoted and…
A: Given that : Volume of ethyl acetate = 10.00 mL It was diluted to 100.00 mL. Volume of KOH = 40.00…
Q: Calcium is determined in serum by microtitration with EDTA. A 100 microliter sample is treated with…
A: Volume of sample (V1) = 100μl = 0.0001L Volume of EDTA (V2) = 0.203mL = 0.000203L Molarity of EDTA…
Q: are doing a titration for a 30.00 ml mixture solution of 0.171 M in X and 0.100 M in CN titrated…
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Q: Standardization of Strong Base Titrant A 0.2042 gram of potassium acid phthalate (represented as…
A: pKa is the negative logarithm of Ka. pKa=-log3.91×10-6 =6-log(3.91) =5.4 The…
Q: Direct titration: 10.90 ± 0.02 mL of an unknown KHP solution required 11.72 ± 0.02 mL of 0.1090 ±…
A: To calculate the concentration of KHP in the unknown solution reported with absolute uncertainty.
Q: What is the MW of calcium carbonate?
A: Since you have asked multiple questions, we will solve the first question for you. If you want any…
Q: Which of the following EDTA titration formats can be used when the analyte reacts too slowly with…
A: EDTA titration formats can be used when the analyte reacts too slowly with EDTA name of the…
Q: (a) 43.5 mL of 0.175 N Hg(NO3)2 (b) 10 mL of 0.03 N KI if the reaction product is Agl (c) 5 litres…
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Q: On titrating 50 ml of 0.01 M KI with 0.01 M AgNO3 . The value of pAg after addition of 30 ml AgNO3…
A: Given data, Volume of KI or I- = 50 ml (as KI is a strong electrolyte, it is completely…
Q: Three more samples of KHP (GFW= 204.23g/mole) weighing 0.8001g, 0.7001, and 0.7666g were titrated…
A: A) (a) 0.8001 g of KHP Number of moles of KHP = 0.8001 / 204.23…
Q: Post-lab Question #2: How many grams of KMNO4 are required to prepare 2.000 L of 0.0300 M KMNO4…
A: W = M x MM x V Where, W = Mass of solute in gram, M = Molarity, MM = Molar of solute in gram/mole,…
Q: A 25.00-mL of 0.15 M NaCI was titrated with 0.1000-M AgNO3, (Ksp for AgCl = 1.82*10-10). What is the…
A: When NaCl reacts with AgNO3 it gives AgCl as precipitate.So the correct answer is option a.
Q: Titration of 0.2120 g of pure Na,C204 (134.0 g/mol) required 43.31ml of KMNO4 solution according to…
A: The reaction that takes place during titration is :2 MnO4-+5Cr2O42-+16H+→2 Mn2+10 CO2 +8H2OMass of…
Q: 2. Assay of Vitamin C: add 100 ml of freshly boiled and cooled water and 10 ml of dilute acetic acid…
A: Given that, Weight of vitamin C taken = 0.2015 g Concentration of Iodine = 0.0515 mol/L Volume of…
Q: Express the titer of 0.120 M EDTA solution (MM 292.00) in mg CaO (MM 56.08) per A 3.15 mg/mL B) 6.73…
A: IMPORTANT POINTS: The language of the question is a little confusing but it simply says to…
Q: 102A 0.2295-g sample of sodium oxalate (Na₂C₂O4-134g/mol; 97.8%) required 35.12mL of a potassium .…
A: Gram milliequivalent weight can be figure out by considering n factor for the sodium oxalate.
Q: Calcium is determined in serum by microtitration with EDTA. A 100-μL sample is treated with two…
A: Volume of sample = V1 = 100ml = 0.1L Volume of EDTA = V2 = 0.203L Molarity of EDTA = M2 = 0.00122 M…
Q: A 50.00-mL aliquot of a 0.100 0 M I− solution was titrated with 0.100 0 M AgNO3. Calculate pAg+ when…
A: Precipitation titration A reaction in which the titrant and analyte form a precipitate is called…
Q: 2. 100 mL tap water is titrated with 20 mL of 0.02 M EDTA solution to dete hardness of the water.…
A: The question is based on quantitative analysis. It involves estimation of hardness content present…
Q: In titration of 100 ml 0.3 Mn²+ with 0.7 M EDTA (pH = 7), when 50 ml EDTA is added what is pMn²+?…
A:
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- Q4 (a) Analyze the importance of dropping mercury electrode on polarography. (b) (i) Calculate the molarity of MgSO4 in a solution containing 1.5 g ofMgSO4 in a volume of 250 mL?(ii) Calculate the weight of MgSO4 in grams which is present in 100mL of 0.076 M MgSO4?(c) Evaluate the key differences between paper chromatography and gaschromatographyAn unknown sample of Cu2+gave an absorbance of 0.262. Then 1.00 mL of solution containing 100 ppm (ug/mL)Cu2+was mixed with 95.0 mL of the unknown and the mixture was diluted to 100 mL in a volumetric flask with deionized water. The absorbanceof the new solution was 0.500. a.Denoting the initial unknown concentrationas [Cu2+]i,write an expression for the final concentrationafter dilution [Cu2+] b.Find [Cu2+]in the unknown.A 500.00 mg vitamin C (MW176.12g/mol) tablet was ground, acidified, and dissolved in H2O to make a 250.0 mL solution. A 50.00 mL aliquot containing vitamin C, KI and starch was analyzed and titrated with 12.31 mL of 0.01042 M KIO3. What is the % (w/w) vitamin C in the tablet? KIO3 + 5 KI + 6 H+ = 3 I2 + 6 K+ + 3 H2O C6H8O6 + I2 = C6H6O6 + 2I- + 2H+ A 67.77 % B 33.89 % C 22.59 % D 3.39 %
- You determine the acetic acid (HOAc) content of vinegar by titrating with a sodium hydroxide standard solution to a phenolphthalein (an indicator) end point. An approximately 5-mL sample of vinegar is weighed on an analytical balance in a weighing boat and this is found to be 5.0268 g. The standard deviation in making a single weighing is 0.2 mg. The sodium hydroxide must be accurately standardised (this means its concentration must be accurately determined) by titrating known mass of high-purity potassium hydrogen phthalate, and three such titrations give molar concentrations of 0.1167, 0.1163 and 0.1164 mol L-1. A volume of 36.78 mL of sodium hydroxide is used to titrate each sample. The standard deviation of the burette used is 0.02 mL. Calculate the percentage of acetic acid in the vinegar and its standard deviation.Using a 25mL pipette, you prepare a standard solution by pipetting 25.00mL of the standard iron solution[0.25g/L] into a 500mL volumetric flask. Then, using a 10mL pipette you transfer a 4mL aliquot of this solution into a 50mL volumetric flask and dilute up to the mark. Calculate the % uncertainty. Question 1 options: 0.65 0.75 0.0075 0.45Standardization of EDTA Solution Weight of pure CaCO3: 0.2517 g % Purity of CaCO3: 98.0% Total volume of standard CaCO3 solution: 250.00 mL Trial 1 2 3 Volume of standard CaCO3 solution (ml) 25.00 25.00 25.00 Final Volume Reading EDTA (ml) 24.30 47.95 24.72 Initial Volume Reading EDTA (ml) 0.00 24.30 0.20 Volume of titrant, EDTA (ml) Molarity of EDTA (M)
- A sample of water from a river was analyzed by titrating a 125 mL aliquot with 0.0210 M EDTA, consuming 22.52 mL. Express the hardness of the water in ppm of CaCO3.A 50.00 (±0.03) mL portion of an HCl solution required 29.71(±0.03) mL of 0.01963(±0.0030) M Ba(OH)2 to reach an end point with bromocresol green indicator. The molar concentration of the HCl is calculated using the equation below (attached image): a.) Calculate the uncertainty of the result (absolute error). M=0.02333(±?????) M b.) Calculate the coefficient of variation for the result. CV= (Sy/y) x 100%Questions 4 and 5 pertain to the following scenario: The patient needs 500 g of the above ointment to use as part of phototherapy.4. Calculate the weight of betamethasone 0.05 % (w/w) ointment required, in grams.5. The above ratio is weight-based. Calculate the volume of mineral oil (sp gr = 0.85), in milliliters.
- Hydrocarbons in the cab of an automobile were measured during trips on the New Jersey Turnpike and trips through the Lincoln Tunnel connecting New York and New Jersey. The total concentrations ( ± standard deviation) of m- and p-xylene wereTurnpike: 31.4 ± 27.0 μg/m3 (32 measurements)Tunnel: 54.9 ± 29.8 μg/m3 (32 measurements)Do these results different at the 95% confidence level?What is the percentage purity of a sample of impure oxalic acid dihydrate if a sample weighing 0.2003 gram requires 29.30 mL of permanganate solution, of which 1.000 mL ≈ 0.006023 g iron?Five white, 500-mg uncoated ascorbic acid (AA) tablets with an average weight of 0.6152-g were pulverized in a mortar. A sample of the powdered ascorbic acid weighing 0.4700-g was placed in an iodine flask and was dissolved in 50-mL H2SO4 then 5-g of KBr was added to the resulting solution. The solution was titrated with 47.81-mL of 0.09640 N STD. KBrO3 to reach a faint yellow endpoint then 3-g KI and 5-mL Starch TS. The blue color solution is then titrated with 2.73-mL of 0.09123 N STD. Na2S2O3 to reach the disappearance of the blue iodostarch complex. MW: KBrO3 = 167.0 ; KIO3 = 214.0 ; Na2S2O3 = 158.11 ; C6H8O6 = 176.12 Compute the milligrams of pure AA per tablet from the assay. 293.3 mg 502.5 mg None of the choices 383.9 mg