To illustrate that the tength of a smooth space curve does not depend on the parameterization used to compute it, calculate the length of one tum of the helix with the following parameterizations. a. r(t) = (cos 41)i + (sin 41)j +4lk, Osts b. r(t) =cos i+ sin k Osts4x C. r(t) = (cos t)i - (sin t) - tk 2xsts0 Note that the helix shown to the right is just one example of such a helix, and does not exactily correspond to the parametrizations in parts a, b, or c

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 18T
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To illustrate that the length of a smooth space curve does not depend on the parameterization used to compute it, calculate the length of one turn of the helix with the following parameterizations.
a. r(t) = (cos 4t)i + (sin 4t)j + 4tk, 0 sts,
b. r(t) = cos
i+ sin
j+=k. 0sts4x
c. r(t) = (cos t)i - (sin t)j - tk,
2nsts0
Note that the helix shown to the right is just one example of such a helix, and does not exactly correspond to the parametrizations in parts a, b, or c.
Transcribed Image Text:To illustrate that the length of a smooth space curve does not depend on the parameterization used to compute it, calculate the length of one turn of the helix with the following parameterizations. a. r(t) = (cos 4t)i + (sin 4t)j + 4tk, 0 sts, b. r(t) = cos i+ sin j+=k. 0sts4x c. r(t) = (cos t)i - (sin t)j - tk, 2nsts0 Note that the helix shown to the right is just one example of such a helix, and does not exactly correspond to the parametrizations in parts a, b, or c.
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