CANNOT BE HAND-WRITTEN - MUST BE TYPEDPart 2: Calculate the time for each hex nut to drop using the equation given (has a square root). Use 3 decimal places. Example: In both strings the first nut drops 0.1m and this gives a time of 0.143 sec.Then calculate the time between impacts. The first interval of time is equal to the time for the 2nd nut to drop - time for the first nut to drop. Continue the process to get all the intervals and put those into tables for each string on hex nuts.Professor indicated my work is incorrect/needs improvement please help, thank you! To understand this quantitatively, consider the following diagrams that modelour string-hex nut systems:3dJWH5dSet d = 10 cm (0.1 m)• Using the kinematic equations, calculate the time it takes for each of theequally spaced masses in the left diagram to hit the ground. Perform thesame calculation for the staggered mass system in the right diagram. Howdoes the time change between impacts of successive masses in bothscenarios? Does this agree with your observations?When we compare the two diagrams we find:Left diagram: d= ut+1/2gt^2t1= square root (2d/g) = 0.143 st2= square root (4d/g)= .202 st3= square root (6d/g) = .247 s3dRight diagram: first mass is = square root (2d/g) = .143 ssecond mass is = square root (6d/g) = .285 sthird mass is = square root (10d/g) = .430 sBased on my observations, the left diagram, which represents the evenly spaced nuts,aligns with the patterns I observed. Similarly, the right diagram, which represents theunevenly spaced nuts, also corresponds to the observations I made. The valuesdepicted in both diagrams accurately reflect the similarities I noticed during theexperiment.6Physics I

The following diagrams that model our string-hex nut systems:- We find out the time it takes for…

Answered: To understand this quantitatively,…

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CANNOT BE HAND-WRITTEN - MUST BE TYPED

Part 2: Calculate the time for each hex nut to drop using the equation given (has a square root). Use 3 decimal places. Example: In both strings the first nut drops 0.1m and this gives a time of 0.143 sec.

Then calculate the time between impacts. The first interval of time is equal to the time for the 2nd nut to drop - time for the first nut to drop. Continue the process to get all the intervals and put those into tables for each string on hex nuts.

Professor indicated my work is incorrect/needs improvement please help, thank you!

To understand this quantitatively, consider the following diagrams that model
our string-hex nut systems:
3
d
JWH
5d
Set d = 10 cm (0.1 m)
• Using the kinematic equations, calculate the time it takes for each of the
equally spaced masses in the left diagram to hit the ground. Perform the
same calculation for the staggered mass system in the right diagram. How
does the time change between impacts of successive masses in both
scenarios? Does this agree with your observations?
When we compare the two diagrams we find:
Left diagram: d= ut+1/2gt^2t1= square root (2d/g) = 0.143 st2= square root (4d/g)
= .202 st3= square root (6d/g) = .247 s
3d
Right diagram: first mass is = square root (2d/g) = .143 s
second mass is = square root (6d/g) = .285 s
third mass is = square root (10d/g) = .430 s
Based on my observations, the left diagram, which represents the evenly spaced nuts,
aligns with the patterns I observed. Similarly, the right diagram, which represents the
unevenly spaced nuts, also corresponds to the observations I made. The values
depicted in both diagrams accurately reflect the similarities I noticed during the
experiment.
6
Physics I

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