Topic: Inverse Functions Question: Determine whether h(x)=1+cosx is a one-to-one function when 0 is less then or equal to x and x is less than or equal to pi (3.14). I'm not sure how to proceed with the 0 and 3.14 values.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.1: Inverse Functions
Problem 51E
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Topic: Inverse Functions

Question: Determine whether h(x)=1+cosx is a one-to-one function when 0 is less then or equal to x and x is less than or equal to pi (3.14). I'm not sure how to proceed with the 0 and 3.14 values.

Expert Solution
Step 1

h(x)=1+cosx

h'(x)=-sinx [using first derivative]

In [0,pi] interval sinx>=0 , so h'(x) is less than or equal to 0. 

h(x) 1+cos
h'(x)-sinx
h'(x)0 in [0,7
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