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Asked Sep 24, 2019
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TRIGONOMETRIC FUNCTIONS
Finding trigonometric ratios given a right triangle
Find csc0, cot0, and sin0, where 0 is the angle shown in the figure.
Give exact values, not decimal approximations.
csc0
?
5
4
cot0
sin0
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TRIGONOMETRIC FUNCTIONS Finding trigonometric ratios given a right triangle Find csc0, cot0, and sin0, where 0 is the angle shown in the figure. Give exact values, not decimal approximations. csc0 ? 5 4 cot0 sin0

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Expert Answer

Step 1

Let the given triangle be ABC with sides BC = a = 4 and AC = c = 5.

А
5
4
b
В
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А 5 4 b В

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Step 2

To Find:

cosece, cote, and sin0 where 0 is the angle shown in the figure
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cosece, cote, and sin0 where 0 is the angle shown in the figure

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Step 3

First, we find the missing side BC by...

i. e AB2BC2 = AC2
So, 42b2 52
b2 52 42
b2 9
b +3
Since x can't be negative, value of b is 3.
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i. e AB2BC2 = AC2 So, 42b2 52 b2 52 42 b2 9 b +3 Since x can't be negative, value of b is 3.

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