Two 500 g blocks of wood are 2.0 m apart on a frictionless table. A 10 g bullet is fired at 400m/s toward the blocks. It passes all the way through the first block, then embeds itself in the second block. The speed of the first block immediately afterward is 6.0m/s. What is the speed of the second block after the bullet stops?

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Asked Nov 25, 2019
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Two 500 g blocks of wood are 2.0 m apart on a frictionless table. A 10 g bullet is fired at 400m/s toward the blocks. It passes all the way through the first block, then embeds itself in the second block. The speed of the first block immediately afterward is 6.0m/s. What is the speed of the second block after the bullet stops?

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Expert Answer

Step 1

Given:

Mass of each block = 500 g

Distance between them = 2 m

Mass of bullet = 10 g

Initial velocity of the bullet = 400 m/s

Initial velocity of the blocks = 0

Step 2

When bullet collide with 1st block

From the conservation of momentum

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т,и + т,и, — ту, +т,v, where, m m, are the masses of bullet and block respectively 4.u2 are the initial velocity of the bullet and block respectively V are the final velocity of the bullet and block respectively plug in the values 10x10 4000 10 x 10 500 x 10 x 6 4 3 10-2 = 100m/s

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Step 3

When bullet collide with 2nd block

Form the...

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mv+m,v = (m,, + mv where m.m, are the masses of bullet and block respectively i,2 are the initial velocity of the bullet and block respectively V,V is the final velocity of the bullet and block respectively after collision plug in the values 10x10 100 0 10x 103 x0500 x 10v 1 500x 10 1000 500 =2m/s V,

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