Question
Asked Nov 21, 2019
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Two blocks are connected by massless string that is wrapped around a pulley. Block 1 has a mass m1=6.70m1=6.70 kg, block 2 has a mass m2=2.90m2=2.90 kg, while the pulley has a mass of 2.50 kg and a radius of 25.6 cm. When the pulley turns, there is friction in the axel that exerts a torque of magnitude 0.660 N m.

If block 1 is released from rest at a height h=0.800h=0.800 m, how long does it take to drop to the floor?

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Expert Answer

Step 1

Given,

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Mass of block 1,m, 6.70 Kg Mass of block 2, m, = 2.90 Kg Mass of pulley,m = 2.50 Kg Radius of pulley,r = 25.6 cm 0.256 m Released from height,h 0.800 m Torque, T 0.660 N-m

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Step 2

Tension and weights acting on the block are shown below,

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R cm 1 2 т,g т,g

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Step 3

As friction is acting about pulley so different amount of tension will be acting at both sides of pulley. This difference in tension in str...

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T-T Friction(f) Torque,T Friction(f)x Radius (r) 0.660 fx(0.256) f 2.58 N

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