Two electrical oscillatorsare used in a heterodynemetal detector to detectburied metal objects (seeFig. P21.41). The detectoruses two identical electricaloscillators in the form of LCcircuits having resonant frequenciesof 725 kHz. Whenthe signals from the twooscillating circuits are combined,the beat frequency iszero because each has thesame resonant frequency.However, when the coil ofone circuit encounters aburied metal object, the inductance of this circuit increases by1.000%, while that of the second is unchanged. Determine thebeat frequency that would be detected in this situation.

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Asked Dec 25, 2019
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Two electrical oscillators
are used in a heterodyne
metal detector to detect
buried metal objects (see
Fig. P21.41). The detector
uses two identical electrical
oscillators in the form of LC
circuits having resonant frequencies
of 725 kHz. When
the signals from the two
oscillating circuits are combined,
the beat frequency is
zero because each has the
same resonant frequency.
However, when the coil of
one circuit encounters a
buried metal object, the inductance of this circuit increases by
1.000%, while that of the second is unchanged. Determine the
beat frequency that would be detected in this situation.

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Expert Answer

Step 1

The resonant frequency is

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fo= 27NIC = 725 kHz

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Step 2

If the capacitance remains constant means the inductance is incr...

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27(1.010L)C (1.010) (725 kHz) V(1.010) = 721.4 kHz

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