Two long, parallel wires carry equal currents in opposite directions. The radius of each wire is a, and the distance between the centers of the wires is d. Show that if the magnetic flux within the wires themselves can be ignored, the self-inductance of a length l of such a pair of wires is L = μ0 l π ln d − a a. (Hint: Calculate the magnetic flux through a rectangle of length l between the wires and then use L = NΦ/I .)
Two long, parallel wires carry equal currents in opposite directions. The radius of each wire is a, and the distance between the centers of the wires is d. Show that if the magnetic flux within the wires themselves can be ignored, the self-inductance of a length l of such a pair of wires is L = μ0 l π ln d − a a. (Hint: Calculate the magnetic flux through a rectangle of length l between the wires and then use L = NΦ/I .)
Chapter14: Inductance
Section: Chapter Questions
Problem 74AP: Two long, parallel wires cy equal currents in opposite directions. The radius of each wire is a, and...
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Two long, parallel wires carry equal currents in opposite directions. The radius of each wire is a, and the distance between the centers of the wires is d. Show that if the magnetic flux within the wires themselves can be ignored, the self-inductance of a length l of such a pair of wires is L = μ0 l π ln d − a a. (Hint: Calculate the magnetic flux through a rectangle of length l between the wires and then use L = NΦ/I .)
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