Asked Sep 20, 2019

Two planes are 1470 mi apart and traveling toward each other. One plane is traveling 80 mph faster than the other plane. The planes pass each other in 1.5 h. Find the speed of each plane.

slower plane     mph
faster plane mph



Expert Answer

Step 1

Let v be the velocity of the slower plane then the velocity of the faster plane is v + 80 and the planes pass each other in 1.5 hours.

That is, the two planes are 1,470 miles apart and one plane relative speed with respective to another is v + v + 80 = 2v +80.

It is known that, the product of time and speed is the value of travelled distance.


Image Transcriptionclose

|(2v+80)x1.5 1,470 3v120 1.4 70 3v 1,350 1,350 1' = 3 v 450 Thus, the speed of the slower plane is 450 miles per hour

Step 2

Substitute v = 450 in v + 80 to find the speed the faster plane as follows,

450+80 = 530.

Thus, the speed of the faster plane is 530 miles per hour.

Step 3

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