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PhysicsQ&A LibraryTwo point charges are fixed on the y axis: a negative point charge q1 = -25 μC at y1 = +0.17 m and a positive point charge q2 at y2 = +0.33 m. A third point charge q = +8.6 μC is fixed at the origin. The net electrostatic force exerted on the charge q by the other two charges has a magnitude of 25 N and points in the +y direction. Determine the magnitude of q2.Question

Asked Nov 6, 2019

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Two point charges are fixed on the *y* axis: a negative point charge *q*_{1} = -25 μC at *y*_{1} = +0.17 m and a positive point charge *q*_{2} at *y*_{2} = +0.33 m. A third point charge *q* = +8.6 μC is fixed at the origin. The net electrostatic force exerted on the charge *q* by the other two charges has a magnitude of 25 N and points in the +*y* direction. Determine the magnitude of *q*_{2}.

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Step 1

Given:

Charge on q_{1 }= -25 µC

Charge on q = 8.6 µC

Position of charge q_{1}, y_{1 }= 0.17 m

Position of charge q_{2}, Y_{2} = 0.33 m

Electrostatic force on q, F = 25 N

Step 2

q_{1 }exerts a force F_{1} on q towards +y direction and can be calculated as

Step 3

Total force on q is F and Force due to q1 is F1. Therefore, force due t...

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