Two small identical conductors, one with a charge of 45 μC and the other with charge -81 μC are brought together so that they touch, then separated. If the force they exert on each other has a size of 0.7 N, how far apart are the two conductors? (in m)

Physics for Scientists and Engineers: Foundations and Connections
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Chapter24: Electric Fields
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Two small identical conductors, one with a charge of 45 μC and the other with charge -81 μC are brought together so that they touch, then separated. If the force they exert on each other has a size of 0.7 N, how far apart are the two conductors? (in m)
(a) 7.14 m
(b) 14.29 m
(c) 6.85 m
(d) 2.04 m
(e) 4.08 m

Expert Solution
Step 1

Given data

The first charge is q1=45 μC

The second charge is q2=-81 μC

The magnitude of the force between the charges is F=0.7 N

 

Let the distance between both the conductors is R.

The force between them can be calculated by using the electrostatic formula.

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