Two tangents converge at an angle 26.3 degrees, which were connected by a reverse curve. The direction of the second tangent is due to East which is having the shortest distance to the point PRC of 131.24 meters. What is the total cost of the reverse curve road in pesos if the bearing of the common tangent is S 44.5 E. Take into consideration that the length of the first tangent is half the length of the second tangent. Station PC is at Sta 10+620. The following are the cost index and specification: Type of Pavement Item 311 (Portland Cement Concrete Pavement) Number of Lanes Four Lanes Width of Pavement = 3.6 m per lane Thickness of Pavement - 25.3 cm Unit Cost = Php 1,587.256 per cubic meters

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FULL SOLUTION PLEASE. DO NOT ROUND OFF PLEASE.The common tangent BC of a reverse curve is 281 m and has an azimuth of 311 degrees . AB is tangent of the first curve whose azimuth is 250 and a distance of 320 m while CD is tangent of the second curve whose azimuth is 211 degrees and a distance of 301 m. If the radius of the second curve is 190 m, determine the following:A. radius of the first curveB. length of the curve from PC to PT