Two vectors have the following magnitude, A = 11.6 m and B = 14.3 m. Their vector product is: AxB = -2.7 m i+ 13.2 m k. What is the angle (in degrees) between the vectors A and B? Hint: Use |AxB| = AB sin(e) Note: Bold face letters represents a vector.

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Q: wo vectors have the following magnitude, A = 14.8 m and B = 14.5 m. Their vector product is:  A⨯B =…

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A: Given  A=5.4m B=11.1 m A⨯B = -2.6 m i + 5.9 m k.