Two vectors have the following magnitude, A= 7.3 m and B = 11.1 m. Their vector product is: AxB = -3.4 m i+ 6.8 m k. What is the angle (in degrees) between the vectors A and B? Hint: Use |AxB| = AB sin(0) Note: Bold face letters represents a vector.

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Q: Two vectors have the following magnitude, A = 8.7 m and B = 6.3 m. Their vector product is: A⨯B =…

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Q: Two vectors have the following magnitude, A = 12.8 m and B = 7.1 m. Their vector product is: A⨯B =…

A: |A⨯B|=x2+y2           =-3.4 m2+11.7 m2           =12.2 m

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Q: Two vectors have the following magnitude, A = 11.7 m and B = 9.8 m. Their vector product is:  A⨯B =…

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Q: Two vectors have the following magnitude, A = 11.8 m and B = 6.8 m. Their vector product is: A.B =…

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Q: Two vectors have the following magnitude, A = 9.6 m and B = 6.8 m. Their vector product is:  A⨯B =…

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Q: Two vectors have the following magnitude, A = 8.7 m and B = 10.6 m. Their vector product is: A.B =…

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A: (a) The scalor product of the given two vectors can be calculated as,

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Q: Two vectors have the following magnitude, A = 5.4 m and B = 11.1 m. Their vector product is:  A⨯B =…

A: Given  A=5.4m B=11.1 m A⨯B = -2.6 m i + 5.9 m k.