Question
Asked Sep 15, 2019
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Find the equation of the circle shown in the figure. 

У
6
4
2
х
8
-6
-2
2
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У 6 4 2 х 8 -6 -2 2

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Expert Answer

Step 1

The equation of circle witj centre(h,k) and radius r is (x-h)^2 +(y-k)^2=r^2. 

Here centre of circle is (-3,3). So, we substitute h=-3 and k=3

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(x-hy-r h -3,k 3 (x-(3)(y-3) (x+3)(y-3)=

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Step 2

Since the circle passes through point (-1,0) , so (-1,0) satisfies the equation of circle.

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(-1+3)(0-3) 4+9 r2213 = 13

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Step 3

Now , we substitute r^2=13 in ...

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(x+3)(y-3) (x+3)+(y313

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