  # use a geometry formula to find the exact value of the definite integral(-2x+4) dx on the interval [3/2,1/2]

Question

use a geometry formula to find the exact value of the definite integral

(-2x+4) dx on the interval [3/2,1/2]

check_circleExpert Solution
Step 1

We have to find the exact value of the definite integral (-2x+4) dx on the interval [3/2,1/2]

As a first step let\'s plot (-2x + 4), x = 3/2 and x = 1/2

Please see the white board. The line in blue is the plot for -2x + 4. The red lines are plot for x = 1/2 and x = 3/2

We have to necessarily find the area of the trapezium ABCD.

Step 2

Using geometry, area of the trapezium ABCD = 1 / 2 x Sum of the parallel sides AD & BC x height between the parallel sides

= 1 / 2 x (AD + BC) x AB

AB = 3/...

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