Question

use a geometry formula to find the exact value of the definite integral

(x/2 +3)dx on interval[-2,4]

Expert Answer

Want to see the step-by-step answer?

Check out a sample Q&A here.

Want to see this answer and more?

Experts are waiting 24/7 to provide step-by-step solutions in as fast as 30 minutes!*

*Response times vary by subject and question complexity. Median response time is 34 minutes and may be longer for new subjects.
Tagged in

Related Calculus Q&A

Find answers to questions asked by students like you.

Q: Kindly help

A: Given information:The given intergal is  

Q: Consider the function g(x) = |(x^2 - 4)/(x+3)| do the following: a) Give the domain of the function ...

A: a) First obtain the singularity for the given function as follows.The denominator of the given fract...

Q: Use the substitution formula Integral from a to b f left parenthesis g left parenthesis x right pare...

A: The given integral is,

Q: Find the values of the convergent series [from k=4 to infinity] E (2/3)3n-1 (-4/7)2n+3 *that E just ...

A: Given information:The given convergent series is  

Q: What is the position at time t of a car that is accelerating at a rate of 5 meters per second square...

A: To determine the position of the car from the given data. (note that s =20 when t=2, not as given)

Q: differentiate f(t) = t^(1/3)/ (t-3) On the solution guide on the first step for the numerator, we ha...

A: Explanation:Consider the term t1/3.It is known that adding and subtracting a same number to any numb...

Q: If y (in 2)2, then O 2eln 2 0 O 2 In 2 1 (in 2)2 O eln 2

A: We have to find derivative of y .Question is given below:

Q: Use the shell method to find the volume of the solid generated by revolving the region bounded by th...

A: (d) First draw the graph of y = x + 6 and y = x2.Find the intersection points as,

Q: Find the area, in square units, bounded above by f(x)=4x2 +9x−24 and below by g(x)=5x2+21x+3.

A: Given that, the area bounded above by f(x)=4x2+9x–24 and bounded below by g(x)=5x2+21x+3.Equate both...