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Use the approximation that vavg = pf/m for each time step.A spring with a relaxed length of 25 cm and a stiffness of 13 N/m stands vertically on a table. A block of mass 79 g is attached to the top of the spring. You pull the block upward, stretching the spring until its length is now 28.4 cm, hold the block at rest for a moment, and then release it. Using a time step of 0.1 s, predict the position and momentum of the block at a time 0.2 s after you release the block. (Assume the +y direction is upward. Express your answers in vector form.)r=      mp=     kg · m/s

Question

Use the approximation that 

vavg = pf/m

 for each time step.

A spring with a relaxed length of 25 cm and a stiffness of 13 N/m stands vertically on a table. A block of mass 79 g is attached to the top of the spring. You pull the block upward, stretching the spring until its length is now 28.4 cm, hold the block at rest for a moment, and then release it. Using a time step of 0.1 s, predict the position and momentum of the block at a time 0.2 s after you release the block. (Assume the +y direction is upward. Express your answers in vector form.)

r
 
 
 
  m
p
 
 
 
 kg · m/s
 

 

check_circleAnswer
Step 1

For a spring mass system, the position is,

kx mg
(0.079)(9.8)
13
- 5.96 cm
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kx mg (0.079)(9.8) 13 - 5.96 cm

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Step 2

The amplitude and angular velocity of the motion is,

A [28.4-25+5.96
936cm
13
0.079
=12.83 rad/s
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A [28.4-25+5.96 936cm 13 0.079 =12.83 rad/s

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Step 3

The expression for the position and ...

y Acosat
dy
DAsin
dt
|2
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Image Transcriptionclose

y Acosat dy DAsin dt |2

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