Question
Asked Oct 15, 2019

Use the function f(x)=x^2-4 and g(x)=2x+20 answer parts (a)-(g).

(a) solve f(x)=0
(b) solve g(x)=0
(c) solve f(x)=g(x)
(d) solve f(x)>0
(e) solve g(x)<_0
(f) solve f(x)>g(x).
(g) solve f(x)>-1

Use the functions f(x)-x-4 and g(x) 2x +20 to answer parts (a)-(g).
(a) Solve fx) 0
(b) Solve g(x) 0
(c) Solve f(x) g(x)
(d) Solve f(x)> 0
(e) Solve g(x)s0
(f) Solve f(x)> g(x)
(g) Solve fx)2 1
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Use the functions f(x)-x-4 and g(x) 2x +20 to answer parts (a)-(g). (a) Solve fx) 0 (b) Solve g(x) 0 (c) Solve f(x) g(x) (d) Solve f(x)> 0 (e) Solve g(x)s0 (f) Solve f(x)> g(x) (g) Solve fx)2 1

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Expert Answer

Step 1

Since, There are multiple number of subparts in the question, we are answering only the first three subparts.

(a) The given functions are

f(x)x-4
g(x) 2x+20
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f(x)x-4 g(x) 2x+20

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Step 2

Substitute f(x)=0 and solve for x as shown below:

f(x)0
-4 = 0
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f(x)0 -4 = 0

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Step 3

(b) Substitute g(x)=0 and solve for x ...

g(r) 0
2x 20 0
x10
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g(r) 0 2x 20 0 x10

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Math

Algebra