Use the given conditions to write an equation for the line in point-slope form and general form.Passing through (3, -9) and perpendicular to the line whose equation is x-2y -9 0The equation of the line in point-slope form is y +9=-2(x-3).(Type an equation. Use integers or fractions for any numbers in the equation.)The equation of the line in general form is0.

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Asked Sep 24, 2019
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Use the given conditions to write an equation for the line in point-slope form and general form.
Passing through (3, -9) and perpendicular to the line whose equation is x-2y -9 0
The equation of the line in point-slope form is y +9=-2(x-3).
(Type an equation. Use integers or fractions for any numbers in the equation.)
The equation of the line in general form is
0.
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Use the given conditions to write an equation for the line in point-slope form and general form. Passing through (3, -9) and perpendicular to the line whose equation is x-2y -9 0 The equation of the line in point-slope form is y +9=-2(x-3). (Type an equation. Use integers or fractions for any numbers in the equation.) The equation of the line in general form is 0.

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Expert Answer

Step 1

The line passes through (3,–9) and perpendicular to the equation x-2y-9=0.

Determine the slope m o...

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х- 2у-9%3D0 -2y x+9 9 -x -2 2 1 which is of the form y mx + 2 c) 2 1 . Slope m 2

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