Question
Asked Oct 21, 2019

Use the identity cos alpha cos beta = 1/2[cos(a-b)+cos(a+b)] to rewrite 2cos3xcos2x as a sum of trig functions. 

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Expert Answer

Step 1

The given ide...

cos(a-B)+ cos(a p)
cos a cos B=
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cos(a-B)+ cos(a p) cos a cos B=

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