Question
Asked Nov 26, 2019
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Use the integral test to determine if the following series converges or diverges.
441 ln n
8
ne
1
First, show that the conditions required for the integral test apply
oo
441 ln z
dz. Enter DNE or±o0 (if appropriate) if the integral diverges. No decimal entries
[A] Find the value of
allowed
441 In x
da
[B] Based on this, does the series converge?
Converges
Diverges
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Use the integral test to determine if the following series converges or diverges. 441 ln n 8 ne 1 First, show that the conditions required for the integral test apply oo 441 ln z dz. Enter DNE or±o0 (if appropriate) if the integral diverges. No decimal entries [A] Find the value of allowed 441 In x da [B] Based on this, does the series converge? Converges Diverges

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Expert Answer

Step 1

From the given information it is required to determine if the series converges or diverges by using the integral test.

f be a function continuous, positive decreasing on [1,∞) such that an = f(n) then,

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f(x)dx converges n n=1

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Step 2

In the given question the given series and corresponding f(x) is:

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441ln(n) Σ оо 8 п n=1 441ln(x) Г(к)-

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Step 3

Now, evaluate the integral to test f...

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441n (x Lds = 441 (x) dx 8 In dx then find the limits: f(x) first evaluate In (x) d-In(x)(x*) - In (x)x d-(In(x))Jx*a dx In (x)x dx 7 -7 In (x)x 1x 7 7 7

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