Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. ex = 8 - 7x, (0, 1) The equation e = 8 - 7x İs equivalent to the equation (x) = e* - 8 + 7x = 0. f(x) İs continuous on the interval [0, 1), F(0) = -7 and 1) = 1.72 Since f(0) < 0 < f(1) there is a number c in (0,1) such that fe) = 0 by the Intermediate Value Theorem. Thus, there is a root of the equation e = 8 - 7x, in the interval (0, 1). Need Help? Read It Watch It
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problem is attached! I got f(1) wrong .
I am completely stuck! I really need help! please and thank you so much!
![Use the Intermediate Value Theorem to show that there is a root of the given
equation in the specified interval.
ex = 8 - 7x, (0, 1)
The equation ex = 8 - 7x İs equivalent to the equation fx) = e* – 8 + 7x = 0. f(x) İS continuous on
the interval [0, 1], f(0) = | –7
and f(1) =| 1.72
Since
f(0)
< 0 < f(1)
v , there is a number c in (0, 1) Such that fc) = 0 by the
Intermediate Value Theorem. Thus, there is a root of the equation e = 8 - 7x, in the
interval (0,1).
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Given
The function is .
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