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TrigonometryQ&A LibraryUse the Law of Sines to show that there is no triangle satisfying angle A=π/3 with opposite side a=2 and side b=5 (Recall the notation that side a is opposite angle A and side bb is opposite angle B).Apply the Law of Sines and solve for sin(B).sin(B)= (5sqrt3)/4In complete sentences, explain why this value for the sin(B) shows that no such triangle exists.Question

Asked Jan 9, 2020

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Use the Law of Sines to show that there is no triangle satisfying angle A=π/3 with opposite side a=2 and side b=5 (Recall the notation that side a is opposite angle A and side bb is opposite angle B).

Apply the Law of Sines and solve for sin(B).

sin(B)= (5sqrt3)/4

In complete sentences, explain why this value for the sin(B) shows that no such triangle exists.

Step 1

According to the law of sine we have

Step 2

Substitute A = π/3, a = 2 and ...

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