Question
Asked Aug 30, 2019
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I believe I have the first part right, but I'm not sure about the second!

 

Use the two-way table below to answer the following question.

 

Question 1: P(> 1 car | 3 to 5 kids) =

Question 2: P(> 3 kids or <= 2 cars) =

Use the two-way table below to answer the following question
Kids
Total
Cars
1
2
3
4
5
6
1
1
1
2
2
2
2
10
4
2
2
1
3
3
2
15
3
0
2
2
0
1
Total
5
5
5
5
5
30
P(> 1 car | 3 to 5 kids)
Question 1
0.6000
P(> 3 kids or <= 2 cars)
Question 2
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Use the two-way table below to answer the following question Kids Total Cars 1 2 3 4 5 6 1 1 1 2 2 2 2 10 4 2 2 1 3 3 2 15 3 0 2 2 0 1 Total 5 5 5 5 5 30 P(> 1 car | 3 to 5 kids) Question 1 0.6000 P(> 3 kids or <= 2 cars) Question 2

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Expert Answer

Step 1

Ques 1   P(>1 car | 3 to 5 kids) 

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P(AJB)=P(A and B) P(B) =P(car3 to 5kids) P 1car and 3 to 5kids) P(3 to 5kids) 9 15 -0.6

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Step 2

Ques 2

P(>3 kids or <...

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P(A or B) P(A) P(B) - P(A and B) =P(>3 kids or=2 cars) P>3 kids and P( 3 kids) P<-2 cars) 2 cars) 14 15 25 30 30 30 26 30 =0.87 |

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