Question

Asked Nov 15, 2019

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Calculate the mass in grams of CH4 gas that can be dissolved in 625. ML of water at 25 Celsius and a CH 4 partial pressure of 2.98 ATM.

Step 1

Given:

Henry’s law constant for methane(CH_{4})=1.4x10^{-3} M/atm

Volume of water=625 mL

Partial pressure of methane=2.98 atm

Temperature=25 degree Celsius

Conversion:

From mL to L:

Volume of water=625 mL

=625/1000

=0.625 L

Step 2

Henry’s law expression is given as

Step 3

By substituting all the values in the above equation, we...

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