Question

Asked Nov 16, 2019

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Step 1

The reaction is written as follows:

5Zn(s) + 2IO_{3}^{- }(aq) + 12H^{+}(aq) →5Zn^{2+}(aq) + I_{2}(s) + 6H_{2}O(l)

The oxidation half reaction is shown in equation (1).

The reduction half reaction is shown in equation (2).

Step 2

The standard cell potential is calculated as follows:

Step 3

The overall reaction is written by combining equation (1) and (2) and multiplying equation (1) by ...

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