Question
Asked Apr 26, 2019
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Using the appropriate Ksp values, find the concentration of NO3 ions in the solution at equilibrium after 700 mL of 0.40 M aqueous Cu(NO3)2 solution has been mixed with 500 mL of 0.30 M aqueous KOH solution. (Enter in M.) (Ksp for Cu(OH)2 is 2.6x10-19).

 

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Expert Answer

Step 1

No Ksp value is necessay to find the concentration of NO3- ions in the solution at equilibrium.

The moles can be calculated as

700 mL of 0.40 M Cu(NO3)2 is: 700mL x 0.40M = 0.280 mol of Cu(NO3)2
500 mL of 0.30 M KOH is: 500mL x 0.30M = 0.150 mol of KOH. 

Step 2

The concentration of NO3- ions can be calculated as


The volume is 1200ml = 1.2 L after mixing the chemicals.  Since NO3- ions does not precipitate out, the NO3- concentration is (note that one Cu(NO3)2 mo...

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Equilibrium Concepts

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