  # Using the chain rule find dy/dx for the function:y=sin(cos(tan(sec(csc(cot(e^((2x^2)(2x)(2)))))))))

Question

Using the chain rule find dy/dx for the function:

y=sin(cos(tan(sec(csc(cot(e^((2x^2)(2x)(2)))))))))

check_circleExpert Solution
Step 1

Given:

Step 2

Formula used: help_outlineImage Transcriptionclose(sinx) cosx dx d (cos.x) sinx dx d (tan x) sec2 x dx (secx) secx tan x dx d (cot x)csc2x dx -(cscx)-cscxcotx dx 11 d e =e* dx fullscreen
Step 3

So, using chain rule the derivative of ‘y&rsquo... help_outlineImage Transcriptionclose>(2)) y =sin(cos(tan(sec(csc (cot(e2x*>2xX2} Sx3 '»]x sincos(tan(sec(csc(cot(e dx d cos(tan(sec(csc(cot(e? x dx dy d tan(sec(csc(cot(e dx x dx d d cot(e dx \$x 8x3 dx dx d dx | fullscreen

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