
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- Using the codon charts in your text (section 6.1), fill in the chart below. [ /8]
Original DNA sequence |
TAC GGA CAC GTT CGC AAC |
mRNA sequence |
|
tRNA anticodons |
|
Amino acid sequence |
Mutated DNA sequence |
TAC GGA CAC ATT CGC AAC |
mRNA sequence |
|
tRNA anticodons |
|
Amino acid sequence |
|
Type of mutation (highlight all that apply) |
Frameshift Nonsense Missense Silent Insertion Deletion Substitution |
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- Complete the box below: Convert the following template strand of DNA bases into its complementary mRNA molecule. Next translate the DNA into a polypeptide chain of amino acids using the Table above. CAATATGGAAGCCGACTCACCCTAATTarrow_forwardIdentify (and highlight or underline) the one nucleotide difference between the original (left) and altered (right) sequencesarrow_forwardDescribe in detail all of the steps necessary to carry out translation. You may write in complete sentences or provide a numbered or bulleted list. Be sure to indicate the role of each item below: Amino acids, mRNA, 30S ribosome, 50S ribosome, tRNA, protein chain, E site, P site, and A site.arrow_forward
- For each mutant, state what change has occurred in the DNA, whether it was a substitution by transition or transversion, sense mutation, nonsense or reading frame change. It must present the codon sequence. Normal nucleotide sequence starting from the third codon: CCC-ACG-GUG-ACG-ACA-CGG-UGG Please show the codon and nucleotide sequence of the mutation.arrow_forwardmRNA Codon Chart: Second letter с บบบ UCU UAU Phe UUC UCC U Ser UAC Tyr UGU UGC Cys UUA UCA Leu UAA Stop UGA Stop A UUG UCG UAG Stop UGG Trp CUU CCU CAU CGU CUC CCC His CAC Leu Pro CUA CCA CAA CGA Arg Gin CUG CCG CAG CGG AUU ACU AAU AUC lle ACC AAC AGU ]Asn Ser AGC A Thr AUA ACA AAA Lys AGA Arg AUG Met ACG AGG GUU GCU GAU GUC GCC Val GAC Asp GGU GGC Ala GUA GCA GUG GCG GAG GGG GAA Glu GGA Gly Amino Acid 3-Letter Codes Name of Amino Name of Amino 3-Letter Code 3-Letter Code Acid Acid Alanine Ala Leucine Leu Arginine Arg Lysine Lys Asparagine sex Methionine Met (start) Aspartic Acid Asp Phenylalanine ebe Cysteine Cve Proline Pro Glutamic Acid Glu Serine Ser Glutamine Gln Threonine Glycine GLK Tryptophan JAR Histidine His Tyrosine Tyr Isoleucine lle Valine Val Exercise: Transcription & Translation 1. Choose 3 DNA Templates. 2. Write the mRNA sequence divided into 3 letter codons. 3. Write the sequence of amino acids. 4. Find the corresponding amino acid sequence and include the letter of…arrow_forwardFIRST BASE UUU- UUC UUA UUG U CUU- CUC -Phe -Leu DNA Sequence tRNA Sequence (anticodon) -Leu CUA CUG AUU- ACU AUC lle ACC AUA ACA Met or AUG Start ACG- GUU GUC GUA GUG mRNA Sequence (codon) AMINO ACID Sequence SECOND BASE C -Val UCU- UCC UCA UCG- CCU CCC CCA CCG GCU GCC GCA GCG Ser -Pro Thr Ala AAG GAU UAU Cys UAC UAA Stop UGA Stop UAG Stop UGG Trp CAU- CGU -His CAC CGC CAA CGA -Gin CAG CGG AAU- AGU- AAC- AGC AAA- AGA AGG GGU- ASP GGC GGA GGG GAC- GAA GAG UGU- Tyr UGC- Asn Lys G Glu Arg 2 1. In your bag is a specific DNA sequence. 2. Copy that sequence in the box below labeled DNA sequence 3. Transcribe the sequence in the appropriate box. 30 Ser 4. Determine the appropriate anticodon sequence. 5. Translate the appropriate sequence into an amino acid sequence using the codon chart above 6. Using the contents of the bag, create your protein. Arg Gly THIRD BASEarrow_forward
- Part of a sequence of DNA from a person without this genetic disease is: TAG TAA AAA CCA CCC AGG Part of a sequence of DNA from a person with a genetic disease is: TAG TAA CCA CCC AGG The possible codons for some amino acids are shown in the table. Amino acid Codons glycine GGU GGC GGA GGG isoleucine AUU AUC phenylalanine UUU UUC serine UCU UCC UCA UCG Which amino acid is missing from a person with this genetic disease? serine glycine O phenylalanine isoleucinearrow_forwardAn anticodon of tRNA has the sequence GCA. What amino acid does this tRNA carry? HINT: you use mRNA codons to read the genetic code chart.arrow_forwardCan you help me solve this sequence question and identifty the mutation?arrow_forward
- If DNA segments changes from GCATAG to GCATGG, this is a: MRNA Codon/Amino Acid Chart First Base Second Base Third Base A G UUU1 Phenylalanine UCUT UAUT FTyrosine (Tyr) UAC UGU, U FCysteine (Cys) UGCJ UUCJ (Phe) UCC Serine (Ser) UCA U UGA - Stop A UUA1 FLeucine (Leu) UUG- UAA1 FStop UAGJ UCG- UGG - Tryptophan (Trp) G CUU CAU1 CCU1 CGUT Histidine (His) CAC- CUC CCC Proline (Pro) CCA CGC FLeucine (Leu) CUA FArginine (Arg) CGA CAA1 Glutamine A CAGJ (Glu) CGG- CUG- CCG- ACU AAUJ Asparagine AUUT AGUT FSerine (Ser) AGC- U AUC FIsoleucine (lle) ACC AACJ(Asn) Threonine A AUA- (Thr) AAA1 FLysine (Lys) AAG- АСА AGA, FArginine (Arg) AGG- A Start Methionine AUG- (Met) ACG- G GUU GCU, GAU1 Aspartic Acid GGU U GAÇJ(Asp) GUC Fvaline (Val) GUA GCC GGC G Alanine (Ala) GCA Glycine (Gly) A GAAJ Glutamic Acid GGA GAG- (Glu) GUG- GCG- GGG- Garrow_forwardUse this mRNA coding sequence as your starting point. This sequence begins with a start codon and ends with a stop codon, so it is only looking at the region of DNA that directly encodes a protein sequence. 5’-AUGCACAAAUUAGAGUACCCCCCAGGAAGGUAG-3’ Make the following mutation in this sequence by changing/adding/removing only one nucleotide. Make the mutation easy to see (a different color, circled, something like that) A frameshift mutationarrow_forwardDuring translation, the formation of peptide bonds between adjacent amino acids requires peptidyl transferase enzyme activity, which is carried out by ______________________. Release Factor 23S rRNA of the large ribosomal subunit 16S rRNA of the small ribosomal subunit tRNA A protein enzyme called peptidyl transferasearrow_forward
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