Question

Using the equations

 H₂ (g) + F₂ (g) → 2 HF (g) ∆H° = -79.2 kJ/mol

C (s) + 2 F₂ (g) → CF₄ (g) ∆H° = 141.3 kJ/mol

2 C(s) + 2 H₂ (g) → C₂H₄ (g) ∆H° = -97.6 kJ/mol

Determine the enthalpy for the reaction

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g).

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Chemical Thermodynamics

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