Using the information provided below, which of the individuals A and B have: i) Genotypic change i) Phenotypic change iii) Genotypic and phenotypic change X is the partial CDNA sequence of the normal CFTR gene. Use this to determine which DNA sequence (A &B) is the DNA extracted from a patient with and without disease. X) ATGGCGGTCACTCGGCAATTTCCCTGGGCTGTACAAACATGGTATGACTCTCTTGGAGCAATAAACA Met. A V IR Q FP W A V Q T WY D SL GA I N.. A) ATGGCGGTCACTCGGCAATTTCCCTGGGCTGTACAAACAGGTATGACTCTCTTGGAGCAATAAACAA Met. B) ATGGCGGTCACTCGGCAATTTCCCTGGGCTGTACAAACTTGGTATGACTCTCTTGGAGCAATAAACA Met. Since this is a complementary DNA (CDNA) The nucleotide "T" can be directly replaced with U to get the MRNA strand. Example: ATG is AUG, TCA is UCA etc Second letter A G UAUTv UGulcvs UACS UAA Stop UGA Stop A UAG Stop UGG Trp G UUU Phe UCU UCU UUC J UGCCYS UCC Ser UUA) UUG Leu UCG UCA CUU CUC CỦA CUG CAUTHIS CACS CAAGIN CGU CCU CCC CCA CCG CGC Leu Pro Arg CGA CAGJ Gin CG AAUAS AGUser AUU AUC le A AUA ACU ACC ACA AAC Asn AAA AGC Thr AUG Met ACG AAGLYS AGG JArg G. GUU GUC GUA GUG GCU GCC GEA Ala GGU GGC GAUT GACASP GGA Gly GAA GAG Glu GGG GCG G. First letter Third letter

Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
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Using the information provided below, which of the individuals A and B have:
i) Genotypic change
ii) Phenotypic change
iii) Genotypic and phenotypic change
X is the partial CDNA sequence of the normal CFTR gene. Use this to determine which DNA sequence (A &B)
is the DNA extracted from a patient with and without disease.
X) ATGGCGGTCACTCGGCAATTTCCCTGGGCTGTACAAACATGGTATGACTCTCTTGGAGCAATAAACA
Met. A V IR Q F P WA V Q T W Y D S L GAI ..
A) ATGGCGGTCACTCGGCAATTTCCCTGGGCTGTACAAACAGGTATGACTCTCTTGGAGCAATAAACAA
Met.
B) ATGGCGGTCACTCGGCAATTTCCCTGGGCTGTACAAACTTGGTATGACTCTCTTGGAGCAATAAACA
Met.
Since this is a complementary DNA (CDNA) The nucleotide "T" can be directly replaced with U to get the mRNA
strand. Example: ATG is AUG, TCA is UCA etc
Second letter
G
UAU
UCU
c Phe UCc
UGU
UUC
U
UUA
UAC JTyr
UGCCYS
Ser
UCA
UCG
UAA Stop UGA Stop A
UAG Stop UGG Trp
UUG Leu
G.
CUU
CCU
CCC
Pro
CAU
CAC Hi.
CAA
CAGJ
CGU
CGC
CUC
CUA
Leu
CCA
Arg
CGA
Gin
CUG
CCG
CGG
AUU
ACU
ACC
ACA
AUG Met ACG
LAsn AGUser
AAC
AUC Ile
A AUA
Thr
AAG Lys AGG JArg
GUU
GUC
G
GUA
GUG
GCU
GCC
Ala
GCA
GAU ASP
GAC
GGU
GGC
Gly
GGA
Asp
Val
GAA
GAG Glu
GGG
GCG
First letter
Third letter
Transcribed Image Text:Using the information provided below, which of the individuals A and B have: i) Genotypic change ii) Phenotypic change iii) Genotypic and phenotypic change X is the partial CDNA sequence of the normal CFTR gene. Use this to determine which DNA sequence (A &B) is the DNA extracted from a patient with and without disease. X) ATGGCGGTCACTCGGCAATTTCCCTGGGCTGTACAAACATGGTATGACTCTCTTGGAGCAATAAACA Met. A V IR Q F P WA V Q T W Y D S L GAI .. A) ATGGCGGTCACTCGGCAATTTCCCTGGGCTGTACAAACAGGTATGACTCTCTTGGAGCAATAAACAA Met. B) ATGGCGGTCACTCGGCAATTTCCCTGGGCTGTACAAACTTGGTATGACTCTCTTGGAGCAATAAACA Met. Since this is a complementary DNA (CDNA) The nucleotide "T" can be directly replaced with U to get the mRNA strand. Example: ATG is AUG, TCA is UCA etc Second letter G UAU UCU c Phe UCc UGU UUC U UUA UAC JTyr UGCCYS Ser UCA UCG UAA Stop UGA Stop A UAG Stop UGG Trp UUG Leu G. CUU CCU CCC Pro CAU CAC Hi. CAA CAGJ CGU CGC CUC CUA Leu CCA Arg CGA Gin CUG CCG CGG AUU ACU ACC ACA AUG Met ACG LAsn AGUser AAC AUC Ile A AUA Thr AAG Lys AGG JArg GUU GUC G GUA GUG GCU GCC Ala GCA GAU ASP GAC GGU GGC Gly GGA Asp Val GAA GAG Glu GGG GCG First letter Third letter
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