Using the isothermal transformation diagram for an iron-carbon alloy of eutectoidcomposition, sketch (mark the microconstituents, eg. a-Fe, Fe,C) and specify thename of the final microstructure (e.g. austenite, pearlite, bainite etc.) of a smallspecimen that has been subjected to the following time-temperature treatment. Ineach case assume that the specimen begins at 760 Cand that is has been held at thistemperature long enough to have achieved a complete and homogeneous austenitestructure.800-Eutectoid temperature140070012006001000500800400300600Mistart)20050%400ME50%)M90%)100200101010101010Time (eoha ileySons, lnc. Al righta reserved(a) Cool rapidly to 350 S, hold for 10' s, then quench to room temperature(b) Cool rapidly to 665 S, hold for 10's, then quench to room temperature(c) Cool rapidly to 150gin 5 seconds, then cool to room temperature(d) Cool rapidly to 300gin 1 second, then cool to room temperature in 10s(3J anjedueITemperature F)

(a) When it is rapidly cools to 350°C and held for 10000 s then the ausentite convert into the…

Answered: Using the isothermal transformation…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Using the isothermal transformation diagram for a 1.13 wt% C steel alloy, determine the final microstructure (in terms of the microconstituents present) of a small specimen that has undergone the following time-temperature treatments. In each case suppose that the sample begins at 920 ° C and that it has been held at this temperature for the timesufficient to achieve a complete and homogeneous austenitic structure. (a) Quickly cool to 250 ° C, hold for 103 s, then cool to room temperature.(b) Quickly cool to 400 ° C, hold for 500 s, then cool to room temperature.(c) Quick cool to 700 ° C, hold for 105 s, then cool to room temperature.(d) Rapidly cool to 650 ° C, hold for 3 s and rapidly cool to 400 ° C, hold that temperature for 25 s and cool to room temperature.(e) Quick cool to 650 ° C, hold for 7 s, then cool to room temperature.
Please do it as early as possible. Name the microstructural products of a eutectoid iron-carbon alloy (0.76 wt% C ) that is first completely transformed to austenite and then cooled to room temperature at a rate of 1000 °C/s
Using the isothermal transformation diagram for a 0.45 wt% C steel alloy (Animated Figure 10.40), determine the approximate percentages of the microconstituents that form the final microstructure of a small specimen that has been subjected to the following time– temperature treatments. In each case assume that the specimen begins at 845°C (1550°F), and that it has been held at this temperature long enough to have achieved a complete and homogeneous austenitic structure.
Part C. Which type of phase transformation is important in heat treatment of steels? (circle one)Peritectic Eutectic Eutectoid Incongruent meltingAt what temperature and overall composition wt% C, does it occur?Write the reaction equation for this transformation, and briefly describe the nature of each of the three important phases that are involved.
A 50%Ni-50%Cu alloy is slowly cooled from 1400°C to 1200°C. Determine (1) At what temperature does the first solid phase form andwhat is the solid’s composition?(2) At what temperature does all liquid solidify and what is thelast remaining liquid’s composition?(3) At 1300°C, estimate the compositions of the solid andliquid.(4) At 1300°C, estimate the weight fractions of the solid andliquid.
Lead-Tin (Pb-Sn) alloys are used in soldering applications. Draw phase diagram and Distinguish between the micro-structure at composition of “Pb40%Sn” and “Pb80%Sn”.
Make a copy of the isothermal transformation diagram for an iron-carbon alloy of eutectoid composition and then sketch and label time-temperature paths on this diagram to produce the following microstructures: 100% fine pearlite. 100% tempered martensite. 50% coarse pearlite, 25% bainite and 25% martensite.
Briefly describe how precipitation hardening happens in Al alloys (how the microstructure evolves as annealing time increases). Why it first forms q” then q’ before q is finally formed? How does the alloy’s strength change during this process? What are the strengthening mechanisms?
1. Why does the tensile strength of steel, which contains only austenite at room temperature, differ fromsteel that shows only pearlite in its microstructure? Give two important reasons for the difference. 2. What general prerequ_isites exist for the formation of martensite in steel? 3. What is an isothermal transformation of a material in the solid state condition? 4. Draw a typical isothermal transformation diagram for plain .carbon eutectoid steel and indicate thevarious decomposition products expected by simple diagrammatic drawing.
Below is shown the isothermal transformation diagram for a 0.45 wt% C iron-carbon alloy. List the microconstituent(s) present for the heat treatment labeled (a)-(c) on this diagram. It is not necessary to state the proportion(s) of the microconstituents. I would love an explaiation aswel on how i whould read this diagram. Thanks
Using the isothermal transformation curve for a Eutectoid steel, determine the final structure of alloy for the following cooling processes
. Using the isothermal transformation diagram for an iron-carbon alloy of eutectoid composition, specify the nature of the final composition in terms of microconstituents present and approximate percentages: a) Rapidly cool to 350 oC, hold for 104 s, and quench to room temperature. b) Rapidly cool to 250 oC, hold for 100 s, and quench to room temperature. c) Rapidly cool to 650 oC, hold for 20 s, rapidly cool to 400 oC, hold for 103 s, and quench to room temperature.

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