Using the scheme of the tent and information below, you must determine the minimum cost required to perform the work painting (with detailed steps). Information : (1) the 2 solid be respectively a pyramid to rectangular base and a prism trapezoidal base. 2) the tent must be painted completely red except the door that must be colored yellow. The semicircle at the- above the door must be from blue color. 3) for red paint, the price is$ 23.50 / pot and a pot covers an area of 1500 m2. 4) for yellow paint, the company "Golden Occasion" request 8,265 / pot which covers 1m2 and for the blue, the price is 4.34 S / pot which covers 30cm2 5) the company "Petit prix" asks 7,29 S / pot which covers 1,1 m ' for its painting yellow and 5,34 S/pot that covers 34cm2 for the Blue. 6) point P is equidistant from A and B and forms a right triangle. Choice of answers (A) $ 619.40 (B) $ 568.54 (C) $ 724.12 (D) $ 343.45
Using the scheme of the tent and information below, you must determine the minimum cost required to perform the work painting (with detailed steps).
Information :
(1) the 2
2) the tent must be painted completely red except the door that must be colored yellow. The semicircle at the- above the door must be from blue color.
3) for red paint, the price is$ 23.50 / pot and a pot covers an area of 1500 m2.
4) for yellow paint, the company "Golden Occasion" request 8,265 / pot which covers 1m2 and for the blue, the price is 4.34 S / pot which covers 30cm2
5) the company "Petit prix" asks 7,29 S / pot which covers 1,1 m ' for its painting yellow and 5,34 S/pot that covers 34cm2 for the Blue.
6) point P is equidistant from A and B and forms a right
Choice of answers
(A) $ 619.40
(B) $ 568.54
(C) $ 724.12
(D) $ 343.45
To find the cost, find the surface area of the tent.
The surface area is the sum of the area of all faces.
Consider the diagram
Area of the yellow color =Area of rectangle = L x W= 1*2 =2m2
Area of semicircle(Blue color)= 1/2* π*(1/2)2 =0.39269908 m2
Area of the trapezoidal face which contains door =1/2(50+18)*22 - (2+0.39269908)=745.60730092 m2
Area of the trapezoidal face which does not have door=1/2(50+18)*22=748m2
Area of the back face rectangle=22x80=1760m2
Area of rectangle SWQR=
=3106.638054 m2
is the length of WQ=SR
Area of triangle TSW:
is the height of the triangle TSW.
Area of the opposite face of the triangle TSW:
Now, find length AP using Pythagoras, AP=56.56854 m
Using AP find the height of the triangle ATW, the height of ATW also 56.56854
Area of triangle ATW =509.1165
Area of the opposite side of the triangle ATW=509.1165
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