Using the substrate Ac-Ser-Gln-Asn-Tyr*Pro-Val-Val-NH2 and 10 nM HIV-1 protease, an inhibitor showed competitive inhibition, and a family of lines of 1/v vs. 1/[substrate] at changing-fixed concentrations of this inhibitor were as below: [Inhibitor] (HM Slope (apparent Km/Vmax) (sec) 17,241 21,072 0 10 24,904 20 28,735 30 32,567 40 The Ki value for this inhibitor is

Using the substrate Ac-Ser-Gln-Asn-Tyr*Pro-Val-Val-NH2 and 10 nM HIV-1 protease, an inhibitor showed competitive inhibition, and a family of lines of 1/v vs. 1/[substrate] at changing-fixed concentrations of this inhibitor were as below: [Inhibitor] (HM Slope (apparent Km/Vmax) (sec) 17,241 21,072 0 10 24,904 20 28,735 30 32,567 40 The Ki value for this inhibitor is

Curren'S Math For Meds: Dosages & Sol

11th Edition

ISBN:9781305143531

Author:CURREN

Publisher:CURREN

Chapter16: Adult And Pediatric Dosages Based On Body Surface Area

Section: Chapter Questions

Problem 5.4P

See similar textbooks

Similar questions

what possible outcome may be produced when the molecular weight of an alcohol antiseptic is increase to a C20, will it still be effective? Explain your answer
In a molecular disease of hemoglobin, Hemoglobin Rainier, Tyr 145β is replaced by Cys, which forms a disulfide bond with another Cysresidue in the same subunit. This prevents the formation of ion pairs that normally stabilize the T state. How does hemoglobin Rainier differ from normal hemoglobin with respect to the Hill coefficient
With, Asp-Cys-Lys-Arg What are the pH buffering regions (pH range)? What is the charge at ph 4? Please explain how you find this out. Thanks!
Why does the apparent KM decrease in the presence ofan uncompetitive inhibitor?
b. Compounds A, B, C, and D are known to be intermediates in the pathway for production of protein E. To determine where the block in protein-E production occurred in each individual, the various intermediates were given to each individuals cel Is in culture. After a few weeks of growth with the intermediate, the cells were assayed for the production of protein E. The results for each individuals cells are given in the following table. A plus sign means that protein E was produced after the cells were given the intermediate listed at the top of the column. A minus sign means that the cells still could not produce protein E even after being exposed to the intermediate at the top of the column. Denote the point in the pathway in which each individual is blocked.
a. Compounds A, B, C, and D are known to be intermediates in the pathway for production of protein E. To determine where the block in protein-E production occurred in each individual, the various intermediates were given to each individuals cel Is in culture. After a few weeks of growth with the intermediate, the cells were assayed for the production of protein E. The results for each individuals cells are given in the following table. A plus sign means that protein E was produced after the cells were given the intermediate listed at the top of the column. A minus sign means that the cells still could not produce protein E even after being exposed to the intermediate at the top of the column. Draw the pathway leading to the production of protein E.
Using the ActiveModel for phosphofructokinase (Trypanosoma), describe the difference between the APO1, AP02, and holoenzyme conformations.
A tetrapeptide, glutamate-glycine-alanine-lysine, is prepared at at concentration of 1 mM (0.001 M) and is measured in the standard setup (pathlength of 1 cm). What is the approximate absorbance of this peptide at 280 nm? Hint: if the peptide contained a single tryptophan, the answer would be about 10. 10 280 1 0
Infuse heparin at 1,200 units per hour from a solution containing 40,000 units of heparin in 500 mL D5W. How many mL/hr will deliver the ordered dosage?
Why Phenylmethylsulfonyl fluoride (PMSF, shown in Fig.) does not inhibit aspartate protease as potent as serine protease?
. You need to prepare 500 μL of a 250 µg/mL bovine gamma globulin solution, for one of your protein standards in the Bradford assay. The available bovine gamma globulin in the lab is in the form of a 2 mg/mL stock solution, and it can be diluted with deionized water. Describe or show below how you would create your desired 250 µg/mL solution.
You have discovered a new hemoglobin variant you are calling Hb-21. You have noticed the following from your studies of Hb-21: - The binding constant of Hb-21 is the same at pH 7.1 and 7.4.- The binding constant curves generated by Hb-21 and O2 are sigmoidal.- The Hill coefficient for Hb-21 is 3.-The binding constant for Hb-21 with O2 in the presence of 5mM 2,3-bisphosphglycerate is about 6-times lower instead of the 8-times lower that is observed under these conditions for the wild type enzyme. Use this information to answer questions: Based on this information which of these features of hemoglobin would you conclude are altered in Hb-21 as compared to the wild type hemoglobin? ____ the cooperativity.____ the amount of T versus R state in the tissues. ____ the Bohr effect. What is the major issue for an individual with the Hb-21 variant? Explain exactly what aspect of hemoglobin’s function is altered.