I.Va240VXL1XL3VE4800 ohmVe4800 ohm240V240VXL24800 ohmFigure 1b) Using the block diagram in Figure 2, draw the connection for measuring the line current ofeach phase in Figure 1.AMMETERCAPACITIVE LOADo 0o 0* 025A 15A* 025A 1.5A* 0.25A 15A4.8ka 2.4k 1.2k4.8kΩ 2.4kΩ 1.2) 48 2.4 1.2kΩRESISTIVE LOADPOWER SUPPLYWATTMETER / VARMETER240/415 V 3AL1L2O L3L1 12 L3L1 12 L3N4.8Ω 2.4k 1.2kΩ 4.8kΩ 2.4kΩ 1.20 48 2.4Ο 1.2ΩVOLTMETERINDUCTIVE LOADCOM 250v sOOVCOM 25OV 50ovCOM 250V 500y4.8kn 2.4kN 1.2kn4. kΩ 24kΩ 1.2 4.8 24kΩ 1.2kΩFigure 2O0000

The given circuit is, And the measuring instruments and loads are

Va 240V XLI S4800 ohm Ve 4800 ohm 240V 240V XL2 4800 ohm Figure 1 b) Using the block diagram in Figure 2, draw the connection for measuring the line current of each phase in Figure 1. AMMETER CAPACITIVE LOAD * 023A 13A : 023A 1A 4.8kn 24kO 1.2kO 4.BkO 24kO 1.2kn 4.8kn 24ko 1.2kO RESISTIVE LOAD POWER SUPPLY WATTMETER / VARMETER 240/415 V A L1 12 O LJ N 4.8kn 2.4k) 1.2kO 4.AkO 24kO 1.20 4.8) 2.4kO 1.2k0 VOLTMETER INDUCTIVE LOAD COM 25oV sO COM 25OV s0v COM 250V s0v 4.8kO 24kO 1.2k 4.8kO 24kO 1.2kO 4.8kO 2.4kn 1.2k O OO O OO O OO O OO 0000

Va 240V XLI S4800 ohm Ve 4800 ohm 240V 240V XL2 4800 ohm Figure 1 b) Using the block diagram in Figure 2, draw the connection for measuring the line current of each phase in Figure 1. AMMETER CAPACITIVE LOAD * 023A 13A : 023A 1A 4.8kn 24kO 1.2kO 4.BkO 24kO 1.2kn 4.8kn 24ko 1.2kO RESISTIVE LOAD POWER SUPPLY WATTMETER / VARMETER 240/415 V A L1 12 O LJ N 4.8kn 2.4k) 1.2kO 4.AkO 24kO 1.20 4.8) 2.4kO 1.2k0 VOLTMETER INDUCTIVE LOAD COM 25oV sO COM 25OV s0v COM 250V s0v 4.8kO 24kO 1.2k 4.8kO 24kO 1.2kO 4.8kO 2.4kn 1.2k O OO O OO O OO O OO 0000

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.28P: For the system shown in Figure 3.34. draw an impedance diagram in per unit by choosing 100 kVA to be...

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