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Verify directly that F is an antiderivative of f.F(X) = V/ 5x2-4; f(x)--5x2-45xF(x) is an antiderivative of f(x) because F(x) - f(x) for allxF(x) is an antiderivative of f(x) because f '(x) - Fx) for all >xF(x) is an antiderivative of rx) because F(x) = rx) for all x.F(x) is an antiderivative of f(x) because f(x) - F(x) + C for all x

Question
Verify directly that F is an antiderivative of f.
F(X) = V/ 5x2-4; f(x)--5x2-4
5x
F(x) is an antiderivative of f(x) because F(x) - f(x) for allx
F(x) is an antiderivative of f(x) because f '(x) - Fx) for all >x
F(x) is an antiderivative of rx) because F(x) = rx) for all x.
F(x) is an antiderivative of f(x) because f(x) - F(x) + C for all x
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Verify directly that F is an antiderivative of f. F(X) = V/ 5x2-4; f(x)--5x2-4 5x F(x) is an antiderivative of f(x) because F(x) - f(x) for allx F(x) is an antiderivative of f(x) because f '(x) - Fx) for all >x F(x) is an antiderivative of rx) because F(x) = rx) for all x. F(x) is an antiderivative of f(x) because f(x) - F(x) + C for all x

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check_circleAnswer
Step 1

It is given that,

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Step 2

Use chain rule differentiate F(x) with respect to x.

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Step 3

From the above calculation it is observed that F’(x) = f(x).

Hence, the option 1 is true, that is, F(x) is an antiderivative of f(x...

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