Water flows steadily from an open tank as shown in the figure. (Figure 1)The elevation of point 1 is 10.0 mm , and the elevation of points 2 and 3 is 2.00 mm . The cross-sectional area at point 2 is 4.80×10−2 m2m2 ; at point 3, where the water is discharged, it is 1.60×10−2 m2m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe. Assuming that Bernoulli's equation applies, compute the volume of water ΔVΔV that flows across the exit of the pipe in 1.00 ss . In other words, find the discharge rate ΔV/ΔtΔV/Δt.
Water flows steadily from an open tank as shown in the figure. (Figure 1)The elevation of point 1 is 10.0 mm , and the elevation of points 2 and 3 is 2.00 mm . The cross-sectional area at point 2 is 4.80×10−2 m2m2 ; at point 3, where the water is discharged, it is 1.60×10−2 m2m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe. Assuming that Bernoulli's equation applies, compute the volume of water ΔVΔV that flows across the exit of the pipe in 1.00 ss . In other words, find the discharge rate ΔV/ΔtΔV/Δt.
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter15: Fluid Mechanics
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Problem 17P: Mercury is poured into a U-tube as shown in Figure P15.17a. The left arm of the tube has...
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Water flows steadily from an open tank as shown in the figure. (Figure 1)The elevation of point 1 is 10.0 mm , and the elevation of points 2 and 3 is 2.00 mm . The cross-sectional area at point 2 is 4.80×10−2 m2m2 ; at point 3, where the water is discharged, it is 1.60×10−2 m2m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe.
Assuming that Bernoulli's equation applies, compute the volume of water ΔVΔV that flows across the exit of the pipe in 1.00 ss . In other words, find the discharge rate ΔV/ΔtΔV/Δt.
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