We add 10mL of 0.1M NaOH to 100mL of 0.1M CH3COOH/ 0.1M CH3COO^-. (Ka = 1.8 x10 ^-5). Using the Henderson-Hasselbach equation, pH=pKa + log [A-]/[HA] a) before the addition of NaOH b) after the addition of NaOH
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We add 10mL of 0.1M NaOH to 100mL of 0.1M CH3COOH/ 0.1M CH3COO^-. (Ka = 1.8 x10 ^-5). Using the Henderson-Hasselbach equation, pH=pKa + log [A-]/[HA]
a) before the addition of NaOH
b) after the addition of NaOH
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