We have a normally distributed population of scores with μ = 25 and σ = 5. We have drawn a large number of random samples with a particular sample size of n = 10 from this population.We want to know what the probability that a sample mean will be equal to or greater than 23.First, what is the z-score for our sample mean of interest, 23?Using the z-score from the previous question, use statistics table to answer the question "What is the probability that a sample mean will be equal to or greater than 23?"

An HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you that the printing speed is actually a Normal random variable with a mean of 17.57 ppm and a standard deviation of 3 ppm. Suppose that you draw a random sample of 11 printers. Part i) Suppose the number of printers drawn is quadrupled. How will the standard deviation of sample mean printing speed change? O A. It will decrease by a factor of 4. OB. It will increase by a factor of 4. O C. It will increase by a factor of 2. O D. It will decrease by a factor of 2. OE. It will remain unchanged. Part ii) Suppose the number of printers drawn is quadrupled. How will the mean of the sample mean printing speed change? O A. It will decrease by a factor of 2. O B. It will decrease by a factor of 4 O C. It will increase by a factor of 4. O D. It will increase by a factor of 2. OE. It will remain unchanged. Part iii) Consider the statement: 'The distribution of the mean…

About 79% of all female heart transplant patients will survive for at least 3 years. Eighty female heart transplant patients are randomly selected. What is the probability that the sample proportion surviving for at least 3 years will be less than 70%? Assume the sampling distribution of sample proportions is a normal distribution. pq The mean of the sample proportion is equal to the population proportion and the standard deviation is equal to n The probability that the sample proportion surviving for at least 3 years will be less than 70% is| (Round to four decimal places as needed.)

The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 5.99 ounces and a standard deviation of 0.21 ounces. Suppose that you draw a random sample of 40 cans. Part i) Using the information about the distribution of the net weight given by the manufacturer, find the probability that the mean weight of the sample is less than 5.94 ounces. (Please carry answers to at least six decimal places in intermediate steps. Give your final answer to the nearest three decimal places). Probability (as a proportion) #