which of the following is the correct answer in the image provided and explain your reason for the choice. We have used Raoult's law to obtain the expression for the freezing point shift of a solution:RT;²XBAfus HAmIf the activity of the solvent is given instead byaa = kĄ XAand the vapor pressures of the pure solvent and solute are P and P, what is the newequation for AT; in terms of the mole fraction of solute?21n kAO AT¡RT;Afus HAmRT;2(In kA- XB)Afus HAmΟ ΔΤΙRT;² In kAAfus HAm2ΔΤRT;²XẠXBAT¡Afus HAmRT;2(In kA- XB)O AT¡fus HĂmRT;²XAXBAT¡ =Afus HÂm

Answered: Image /qna-images/answer/bc188eb9-6642-432a-954c-35f3cb26d23f.jpg

We have used Raoult's law to obtain the expression for the freezing point shift of a solution: RT; :2XB AT¡ Afus Him If the activity of the solvent is given instead by aa = kA XA and the vapor pressures of the pure solvent and solute are P: and P, what is the new equation for ATf in terms of the mole fraction of solute? RT; "In kA Afus HĂm AT¡ = RT;2(In kA- XB) Afus HAm AT¡ = RT;2 In kA Afus HĂm AT¡ RT;²XAXB Afus HÂm Ο ΔΤ- RT;2(In ka-XB) ΔΤ Afus HAm RT;'XAXB Ο ΔΤ 2 fus HAm

We have used Raoult's law to obtain the expression for the freezing point shift of a solution: RT; :2XB AT¡ Afus Him If the activity of the solvent is given instead by aa = kA XA and the vapor pressures of the pure solvent and solute are P: and P, what is the new equation for ATf in terms of the mole fraction of solute? RT; "In kA Afus HĂm AT¡ = RT;2(In kA- XB) Afus HAm AT¡ = RT;2 In kA Afus HĂm AT¡ RT;²XAXB Afus HÂm Ο ΔΤ- RT;2(In ka-XB) ΔΤ Afus HAm RT;'XAXB Ο ΔΤ 2 fus HAm

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.26QAP

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