Wekjr command-line argument n and prints an n-by-n pattern like the ones below. Include two space characters between each + and - character. example: input= 4 output = + - - + - + + - - + + - + - - +.
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Wekjr command-line argument n and prints an n-by-n pattern like the ones below. Include two space characters between each + and - character.
example: input= 4
output = + - - +
- + + -
- + + -
+ - - +.
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- A bit shift is a procedure whereby the bits in a bit string are moved to the left or to the right. For example, we can shift the bits in the string 1011 two places to the left to produce the string 1110. Note that the leftmost two bits are wrapped around to the right side of the string in this operation. Define two scripts, shiftLeft.py and shiftRight.py, that expect a bit string as an input. • The script shiftLeft shifts the bits in its input one place to the left, wrapping the leftmost bit to the rightmost position. • The script shiftRight performs the inverse operation. • Each script prints the resulting string. An example of shiftLeft.py input and output is shown below: Enter a string of bits: Hello world! ello world!H An example of shiftRight,py input and output is shown below: Enter a string of bits: Hello world! !Hello worldCommand line arguments are passed to int main(int argc, char** argv) as arguments argc and argv. You should assume that argc is at ebp+8 and argv is at ebp+12. 00000000 <what>: 0: push %ebp 1: mov %esp,%ebp 3: sub $0x10,%esp 6: mov 0x8(%ebp),%eax 9: add $0x4,%eax c: mov %eax,-0x4(%ebp) f: mov 0x8(%ebp),%eax 12: imul 0xc(%ebp),%eax 16: mov %eax,-0x8(%ebp) 19: mov 0x8(%ebp),%eax 1c: sub 0xc(%ebp),%eax 1f: mov %eax,-0xc(%ebp) 22: mov -0x4(%ebp),%edx 25: mov -0x8(%ebp),%eax 28: add %eax,%edx 2a: mov -0xc(%ebp),%eax 2d: add %edx,%eax 2f: leave 30: ret00000031 <main>: 31: lea 0x4(%esp),%ecx 35: and $0xfffffff0,%esp 38: pushl -0x4(%ecx) 3b: push %ebp 3c: mov %esp,%ebp 3e: push %ebx 3f: push %ecx 40: sub $0x10,%esp 43: mov %ecx,%ebx 45: mov 0x4(%ebx),%eax 48: add $0x4,%eax 4b: mov (%eax),%eax 4d: sub…I am still getting the wrong output with the updated code with the fix. This is the updated coded that you provided: .data .globl main .textmain: # compute the next state of the LFSR for each input state li $a0, 0x00000001 jal lfsr_next_state move $t0, $v0 li $a0, 0xdeadbeef jal lfsr_next_state move $t1, $v0 li $a0, 0x200214c8 jal lfsr_next_state move $t2, $v0 li $a0, 0x00000000 jal lfsr_next_state move $t3, $v0 # print the output states li $v0, 1 move $a0, $t0 syscall li $v0, 1 move $a0, $t1 syscall li $v0, 1 move $a0, $t2 syscall li $v0, 1 move $a0, $t3 syscall # exit the program li $v0, 10 syscall # Function to compute the next state of an LFSR# Input parameter: $a0 = current state# Output: $v0 = next statelfsr_next_state: # Initialize upper mask with…
- Write a program that takes a single integernas a command-line argumentand finds its prime factors, excluding 1. The output should consist of asingle line listing each prime factor in non-decreasing order, separated by aspace. Ifnis prime, just printnitself. If there are repeat factors, print thefactor as many times as it dividesn. You can assume that2≤n≤231−1(i.e.,nwill fit in a signed 32-bit integer). ./factor 247 13 19. /factor 7 7 ./factor 32 2 2 2 2 2A common random number generating function is Xi = (A * Xi-1 + C ) mod M where X0 is known as the seed. Write a MIPS Assembly Language program to request and read the equation parameters A, C, M, and X0. Then generate a list of 100 values. Compute the average and standard deviation where all values are recorded as integers.Please give flowchart for bash script read-p "Enter a number: " number read -p "Enter a minimum value: " minvalue read -p "Enter a maximum value: " maxvalue count=0 for ((i=$minvalue; i<=$maxvalue; i++)); do if [[ $((i % 2)) -eq 0 ]] && [[ $((i % number)) -eq ]]; then echo $i count=$((count + 1)) fi done echo "count = $count"
- In C programming language, write a program that accepts an integer on the command line and prints the number in hexadecimal followed by a count of the number of set (1) bits in that integer. example: decimal number is 1111 hexadecimal is 457 bit set is 6Write a general-purpose program that is able to add two 8 bytes length numbers. Numbers are saved in EBX: EAX and EDX: ECX Consider this sample call: Number1 QWORD = 1234567898765432h Number2 QWORD = 1234567898765432h Please write code in Masm (Microsoft assembly) No High-Level Assembly. And please don't separate the variables, keep it as it is. If you do split it please do it in the code part. If possible please use 1 loop anything more than inc, dec, mov, xchg, I don't know how to do that yet.Write an HLA Assembly language program that prompts for a specific int8 value named n and then displays a repeated digit pattern starting with that number. The repeated digit pattern should show all the odd numbers from 1 up to that number followed by all the even numbers from 2 up to that number. Shown below is a sample program dialogue. Gimme a integer value to use as n: 6The big number is: 135246Gimme a integer value to use as n: 11The big number is 1357911246810 (Hint: I would recommend you write it first in C or Visual Basic and then translate your lines of code, one-by-one, into a assembly statements, just like our good friend mr. compiler does.)(Hint: Since we don't really know how to do much math at this point, start your first loop at 1 and the second loop at 2 and then increment by 2 in each loop until you reach n...)
- Create a class RLE that uses fixed-length encoding and relatively few distinct symbols to condense ASCII bytestreams, including the code as a component of the encoded bitstream. Add code to compress() to create an alphabet using all of the message's unique characters. Then prepend alfa (8-bit encoding plus its length) to the compressed bitstream. Finally, add code to expand() to read the alphabet before expansion.This is the updated code that I have: .data .globl main .textmain: # compute the next state of the LFSR for each input state li $a0, 0x00000001 jal lfsr_next_state move $t0, $v0 li $a0, 0xdeadbeef jal lfsr_next_state move $t1, $v0 li $a0, 0x200214c8 jal lfsr_next_state move $t2, $v0 li $a0, 0x00000000 jal lfsr_next_state move $t3, $v0 # print the output states move $a0, $t0 li $v0, 1 syscall move $a0, $t1 li $v0, 1 syscall move $a0, $t2 li $v0, 1 syscall move $a0, $t3 li $v0, 1 syscall # exit the program li $v0, 10 syscall # Function to compute the next state of an LFSR# Input parameter: $a0 = current state# Output: $v0 = next statelfsr_next_state: # Initialize upper mask with 0x7fff and lower mask with 0x8000 lui $t0, 0x7fff ori $t0, $t0,…By defining a 32-bit integer variable named x in SAL language, if the number of "0s" in the binary representation of this variable is less than the number of "1" s, "less", if the number of "0" s more than "1" s, "more" and otherwise write a program that says "equal" to the screen. For example, if the binary representation of our variable is "00110010010100100011100010101000", the message to be written on the screen should be "more".
