WHAMM Is a nucleation promoting factor. Depicted above is a pyrene actin polymerization assay performed with the following reaction conditions 1: Actin + Arp2/3 + WHAMM (active isoform); 2-5: Actin + Arp2/3 + WHAMM (active isoform) and increasing concentrations of Rab1; or 6: actin alone. What effect does Rab1 have on branched actin polymerization? Actin +Arp2/3 + 500nM WHAMM + 0.2x Rab1(M) + 1.0x Rab1(M) + 2.0x Rab1(M) + 3.0x Rab1(M) Actin alone 1.0 0.5 0.0 1000 2000 Time (s) F-actin (RFU)

WHAMM Is a nucleation promoting factor. Depicted above is a pyrene actin polymerization assay performed with the following reaction conditions 1: Actin + Arp2/3 + WHAMM (active isoform); 2-5: Actin + Arp2/3 + WHAMM (active isoform) and increasing concentrations of Rab1; or 6: actin alone. What effect does Rab1 have on branched actin polymerization? Actin +Arp2/3 + 500nM WHAMM + 0.2x Rab1(M) + 1.0x Rab1(M) + 2.0x Rab1(M) + 3.0x Rab1(M) Actin alone 1.0 0.5 0.0 1000 2000 Time (s) F-actin (RFU)

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

QUESTION NO. 1 Cystic fibrosis is a frequent generic disease of Caucasians. The CF gene codes for a protein called the cystic fibrosis transmembrane conductance regulator (CFTR) which functions as a cAMP-regulated chloride channel. The protein has two membrane-spanning domains, two domains that interact with ATP, and one regulatory domain. The most common defect is in the gene for one of the ATP binding domains. The result is a protein that does not fold correctly in the endoplasmic reticulum, is not properly glycosylated, and is nor transported to the cell surface. Rather, it is degraded in the cytosol within proteasomes. Drugs that foster chaperone interaction with the mutant protein are a potential therapeutic approach. Chaperones A. are always required to direct the folding of proteins. B. when bound to protein increase the rate of protein degradation. C. usually bind to strongly hydrophilic regions of unfolded proteins. D. sometimes maintain proteins in an…
QUESTION 10 Remdesivir is converted in vivo to CMP analog and then phosphorylated to CTP analog. a successful treatment for Ebola. There are more than 1 correct answers in the other choices. a potential chain terminator for the replication of RNA viral genome
Question 23 options: A newly discovered colon cancer cell line is established from a tumour sample derived from a patient with colon cancer. To understand more about this cell line and how it is different from normal cells, some experiments on the cell cycle of the colon cancer line are carried out. The cells are examined under the phase contrast microscope and the length of mitosis was found to be 90 minutes. Next, a DNA marker is used to find out how long DNA synthesis takes and indicates that DNA synthesis takes 3 hours. There is a gap between DNA synthesis and mitosis of 3.5 hours and a gap between mitosis and DNA synthesis of 4 hours. What is the total length of the cell cycle? _____ hours?
Question 16: One of the two genes known to be mutated in cases of Hypokalemic periodic paralysis (which is inherited in an autosomal dominant pattern but known to affect males more often than females) is the calcium voltage-gated channel subunit alpha1 S (CACNA1S). What is known about the gene is recorded here: https://www.ensembl.org/Homo_sapiens/Gene/Summary?db=core;g=ENSG00000081248;r=1:201039512-201112451 Please navigate to the link above and use the information and link-outs from the page to answer the following question. GIVE YOUR ANSWER AS A NUMBER ONLY, NO UNITS: What is the size in amino acid residues of the CACNA1S transcript named CACNA1S-202?
QUESTION 10 A 48-year-old female patient has breast carcinoma and presents to the hospital outpatient unit complaining of low energy. The physician orders hemoglobin and hemocrit counts, which were performed. After evaluation, it is determined the patient has anemia in neoplastic disease. The physician orders 3 units of packed red blood cells, which are transfused on the unit. Which coding is best for the blood products? (See the HCPCS options below.) HCPCS Code Descriptor P9010 Whole blood for transfusion, per unit P9021 Red blood cells for transfusion, per unit P9060 Fresh frozen plasma for transfusion, per unit, donor retested P9615 Catheterization for collection of specimen P9045 Infusion, albumin, 5%, 250 ml A. P9021 B. P9021 X 3 C. P9045, P9060 D. P9010 X 3, P9615
Question 14 One of the two genes known to be mutated in cases of Hypokalemic periodic paralysis (which is inherited in an autosomal dominant pattern but known to affect males more often than females) is the calcium voltage-gated channel subunit alpha1 S (CACNA1S). What is known about the gene is recorded here: https://www.ensembl.org/Homo_sapiens/Gene/Summary?db=core;g=ENSG00000081248;r=1:201039512-201112451 Please navigate to the link above. Use the left-hand menu to view the sequence for CACNA1S, and answer the following question. ANSWER ONLY IN UPPERCASE LETTERS, NO UNITS. What are the last six nucleic acid bases of exon 1? Answer: The last six nucleic acid bases of CACNA1S, exon 1 are Blank ...
Question 12 One of the two genes known to be mutated in cases of Hypokalemic periodic paralysis (which is inherited in an autosomal dominant pattern but known to affect males more often than females) is the calcium voltage-gated channel subunit alpha1 S (CACNA1S). What is known about the gene is recorded here: https://www.ensembl.org/Homo_sapiens/Gene/Summary?db=core;g=ENSG00000081248;r=1:201039512-201112451 Please navigate to the link above and ensure that you click to reveal the transcript table. Then use the information in the table to answer the following question. PLEASE GIVE YOUR ANSWER AS A NUMBER ONLY, NO UNITS What is the size in base pairs of the CACNA1S transcript named CACNA1S-202? Answer: The size of the CACNA1S transcript named CACNA1S-202 is Blank ... base pairs.
Question 24 pts When we are vaccinated against SARS-CoV-2, what happens? (select all correct answers) Group of answer choices a) Our adaptive immune system becomes primed to recognize the SARS-CoV-2 virus. b) Our DNA becomes modified. c) We will permanently have viral proteins in our cells d) Our cells will make a partial or complete viral protein, which our immune system will recognize as foreign. e) Memory cells will be ready for a new infection.
Question 13 One of the two genes known to be mutated in cases of Hypokalemic periodic paralysis (which is inherited in an autosomal dominant pattern but known to affect males more often than females) is the calcium voltage-gated channel subunit alpha1 S (CACNA1S). What is known about the gene is recorded here: https://www.ensembl.org/Homo_sapiens/Gene/Summary?db=core;g=ENSG00000081248;r=1:201039512-201112451 Please navigate to the link above and use the information and link-outs from the page to answer the following question. GIVE YOUR ANSWER AS A NUMBER ONLY, NO UNITS: What is the size in amino acid residues of the CACNA1S transcript named CACNA1S-202? Answer: The size of the CACNA1S transcript named CACNA1S-202 is Blank ... amino acid residues.
Question:- 17. The optimal volume for blood-culture collection on adults is a. 20 mL of blood per bottle b. precisely 10 mL of blood in each of two bottles c. 20 mL of blood distributed betvveen two bottles but not exceeding 12 mL per vial d. dependent upon the patient's body weight
Question 29 PCR is a technique that: produces information regarding the sequence of nitrogenous bases virtually eliminates operator error from DNA analysis All of these can produce many exact copies of segments of DNA provides a statistical analysis of the nitrogenous-base pairings
Question 6 In the first part of the experiment, there were only a few colonies on the streptomycin positive plate. In the second part, there are a large number of colonies on the streptomycin positive plate that was inoculated with the antibiotic resistant strain. What is the most likely explanation for this difference? 1. The antibiotic resistant strain was composed of a large number of individuals with resistance to streptomycin 2. The exposure to streptomycin caused a mutation in a few individuals