Asked Nov 29, 2019

What amount of heat is required to vaporize 155.95 g of ethanol (C₂H₅OH)? (∆Hvap = 43.3 kJ/mol)


Expert Answer

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ΔHvap = 43.3 kj/mol



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Number of moles of ethanol is calculated as follows Mass Moles Molar mass 155.95g Moles 46 Moles 3.39


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