Asked Sep 2, 2019

What are the bond-line formulas for the following compounds?

a. 6-butyl-4,7-diethylundecane
b. 1-bromo-3-ethyl-5-methylcyclohexane
c. trans-1,3-dimethylcyclopentane

d. 1-bromopropane (the most stable Newman projection)
e. trans-1,2-dibromocyclohexane (the most stable chair conformation)


Expert Answer

Step 1

Bond line formula has to be drawn for the given compounds.


Condensed structure is the line diagram, the carbon-carbon bonds are represented with lines, and hydrogens are absent entirely.


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Bond line formula for 6-butyl-4,7-diethylundecane: The given compound 6-butyl-4,7-diethylundecane, therefore the given compound has eleven carbon chain is parent chain. It has butyl group at sixth carbon atom, fourth and seven carbon has ethyl group Therefore, the bond line formula for 6-butyl-4,7-diethylundecane is given below Parent chain 8 10 6 10 8 6 3 5 7 9 11 9 11 11 carbon atoms 6-butyl-4,7-diethylundecane

Step 2

Bond line formula for 1-bromo-3-ethyl...


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Bond line formula for 1-bromo-3-ethyl-5-methylcyclohexane: The given compound 1-bromo-3-ethyl-5-methylcyclohexane, therefore the given compound has six carbon chain is parent chain and it is in cyclic form, hence it is called as cyclohexane It has ethyl group at third carbon atom, methyl group at fifth carbon atom Therefore, the bond line formula for 1-bromo-3-ethyl-5-methyleyclohexane is given below Parent chain Br 1 6 Br 6 5 3 4 4 1-bromo-3-ethyl-5-methylcyclohexane 6 carbon atoms LC


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