What are the magnitude and the direction of the force on a -5.31 nC charge in an electric field of +2750 N/C i^-8830 N/C j^? Answer is 49.1uN 107.3 w respect to the x axis using F=qE i^ means up(?) what does j^ mean?  How is this set up?Thanks

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What are the magnitude and the direction of the force on a -5.31 nC charge in an electric field of +2750 N/C i^-8830 N/C j^?

Answer is 49.1uN 107.3 w respect to the x axis using F=qE

i^ means up(?) what does j^ mean?  How is this set up?

Thanks

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Force is given by,

Explanation for unit vectors:

In the above expression, i and j represent unit vectors along x and y directions respectively.

Magnitude of the force is,

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